The nails can puncture the tires of the vehicles making them deflated after a while. The process of tire deflation due to a puncture is due to the process called an effusion. Thus, option c is correct.
<h3>What is effusion?</h3>
Effusion is the process that defines the escape of the fluids or gases from a system through an outlet with a small diameter compared to the mean free path of the molecules.
When a tire is punctured then the gas from the tire starts to move out through the hole through effusion. This leads to deflation of the tire after some time as all the gas present inside had moved out completely.
Therefore, option c. a punctured tire deflates due to effusion.
Learn more about effusion here:
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276 grams of carbon in 23.0 moles
Answer : The correct option is, (b) +115 J/mol.K
Explanation :
Formula used :
![\Delta S=\frac{\Delta H_{vap}}{T_b}](https://tex.z-dn.net/?f=%5CDelta%20S%3D%5Cfrac%7B%5CDelta%20H_%7Bvap%7D%7D%7BT_b%7D)
where,
= change in entropy
= change in enthalpy of vaporization = 40.5 kJ/mol
= boiling point temperature = 352 K
Now put all the given values in the above formula, we get:
![\Delta S=\frac{\Delta H_{vap}}{T_b}](https://tex.z-dn.net/?f=%5CDelta%20S%3D%5Cfrac%7B%5CDelta%20H_%7Bvap%7D%7D%7BT_b%7D)
![\Delta S=\frac{40.5kJ/mol}{352K}](https://tex.z-dn.net/?f=%5CDelta%20S%3D%5Cfrac%7B40.5kJ%2Fmol%7D%7B352K%7D)
![\Delta S=115J/mol.K](https://tex.z-dn.net/?f=%5CDelta%20S%3D115J%2Fmol.K)
Therefore, the standard entropy of vaporization of ethanol at its boiling point is +115 J/mol.K
Gas is not a liquid, hope this helps, o and next time you might wanna put the answer choices thanks
Answer: pH of the solution is 12
Explanation:
NaOH —> Na+ + OH-
NaOH = 0.01M
Na+ = 0.01M
OH- = 0.01M
pOH = —log [OH-] = —log [0.01]
pOH = 2
pH + pOH = 14
pH = 14 — pOH = 14 — 2 = 12
pH = 12