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3 years ago

A sample of 1L of gas in a container at-73C has a pressure of 32.2inHg. To

Chemistry

1 answer:

Goryan [66]3 years ago

8 0

Answer:

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Send your location, come through

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And I can't be without you

Why can't I find no one like you?

I can't sleep no more

In my head, we belong

And I can't be without you

Why can't I find no one like you?

Explanation:

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Define position and reference point in your own words. Dont copy and paste!

irga5000 [103]

Answer: The beginning stage you decide to depict the area, or position, of an object.

Explanation: starting point or position

4 0

3 years ago

(6) 在 420 毫升的柳橙汁中,柳橙原汁對水的比是4:3,加入<br>100 毫升的水後,柳橙原汁對水的比是多少?

Eva8 [605]

Answer:

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2 years ago

Calculate the molality, molarity, and mole fraction of FeCl3 in a 29.5 mass % aqueous solution (d = 1.283 g/mL).

faltersainse [42]

Answer:

molality FeCl3= 2.579 molal

molarity FeCl3 = 2.333 M

mol fraction FeCl3 = 0.0444

Explanation:

Step 1: Data given

Mass % = 29.5 %

Density = 1.283 g/mL

Molar mass FeCl3 = 162.2 g/mol

Step 2: Calculate mass solution

Suppose we have 1L = 1000 mL solution

Mass solution = 1.283 g/mL * 1000 mL = 1283 grams

Step 3: Calculate mass FeCl3

Mass FeCl3 = 0.295 * 1283 grams

Mass FeCl3 = 378.485 grams

Step 4: Calculate mass of water

Mass water = 1283 - 378.485 = 904.515 grams

Step 5: Calculate moles FeCl3

Moles FeCl3 = mass FeCl3 / molar mass FeCl3

Moles FeCl3 = 378.485 grams / 162.2 g/mol

Moles FeCl3 = 2.333 moles

Step 6: Calculate moles H2O

Moles H2O = 904.515 grams / 18.02 g/mol

Moles H2O = 50.195 moles

Step 7: Mol fraction FeCl3

Mol fraction FeCl3 = 2.333 / (50.195+2.333)

Mol fraction FeCl3 = 0.0444

Step 8: Calculate molality

Molality = moles FeCl3 / mass H2O

Molality = 2.333 moles / 0.904515 kg

Molality = 2.579 molal

Step 9: Calculate molarity

Molarity = moles / volume

Molarity FeCl3 = 2.333 moles / 1 L

Molarity FeCl3 = 2.333 M

8 0

3 years ago

A 17.4 L sample of oxygen gas (O2) was collected at a temperature of 23.0°C and a pressure of 2.18 atmospheres. What volume woul

timofeeve [1]

The volume of the gas at STP = 35.01 L

<h3>Further explanation</h3>

Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure).

In general, the gas equation can be written

$\large {\boxed {\bold {PV = nRT}}}$

where

P = pressure, atm

V = volume, liter

n = number of moles

R = gas constant = 0.08206 L.atm / mol K

T = temperature, Kelvin

V=17.4 L

T = 23 + 273 = 296 K

P = 2.18 atm

$\tt mol=n=\dfrac{PV}{RT}\\\\n=\dfrac{2.18\times 17.4}{0.082\times 296}\\\\n=1.563$

The volume of the gas occupy at STP :

$\tt 1.563\times 22.4=35.01~L$

6 0

3 years ago

Compare the diagrams of the chemical structures of the two major categories of energy providing molecules in our food: carbohydr

alisha [4.7K]

Answer:

cfre

Explanation:

4 0

2 years ago