Using the combined gas law, where PV/T = constant, we first solve for PV/T for the initial conditions: (4.50 atm)(36.0 mL)/(10.0 + 273.15 K) = 0.57213.
Remember to use absolute temperature.
For the final conditions: (3.50 atm)(85.0 mL)/T = 297.5/T
Since these must equal, 0.57213 = 297.5/T
T = 519.98 K
Subtracting 273.15 gives 246.83 degC.
Answer:
B. The reactants will react to produce more H₂O
Explanation:
Given the reaction
2H₂+O₂→2H₂O
A decrease in the amount of H₂O will cause the reaction to produce more H₂O. When you change something, the reaction seeks to undo that change.
Answer: They are typically smaller than spiral galaxies.
Some show evidence for prior collision or close encounter with another galaxy.
They exhibit vigorous star-forming activity.
Irregular galaxies are typically smaller than spiral or normal ellipticals, of irregular form, and without spiral arms. Irr I galaxies are often characterized by lots of gas, dust, and associated star formation. Irr II galaxies have forms that indicate prior collisions or close encounters with other galaxies. Irregular galaxies are one of the most common types of galaxies.
The answer is (2) Copper. Because copper is consist of atom. If it is decomposed, the atom will be changed. While chemical change is just the break down and form of chemical bonds between atoms.
The first and Third graph
