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3 years ago

Answer the following questions regarding the equation:

Physics

1 answer:

scoundrel [369]3 years ago

5 0

Explanation:

1) This is a synthesis reaction (two or more reactants combine to form a single product).

2) The coefficients are added to balance the reaction.

3) Adding the states of matter (solid, liquid, gas) will make the reaction more precise.

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Two polarizers A and B are aligned so that their transmission axes are vertical and horizontal, respectively. A third polarizer

Reptile [31]

Answer:

Explanation:

Let the angle between the first polariser and the second polariser axis is θ.

By using of law of Malus

(a)

Let the intensity of light coming out from the first polariser is I'

$I' = I_{0}Cos^{2}\theta$ .... (1)

Now the angle between the transmission axis of the second and the third polariser is 90 - θ. Let the intensity of light coming out from the third polariser is I''.

By the law of Malus

$I'' = I'Cos^{2}\left ( 90-\theta \right )$

So,

$I'' = I_{0}Cos^{2}\theta Cos^{2}\left ( 90-\theta \right )$

$I'' = I_{0}Cos^{2}\theta Sin^{2}\theta$

$I'' = \frac{I_{0}}{4}Sin^{2}2\theta$

(b)

Now differentiate with respect to θ.

$I'' = \frac{I_{0}}{4}\times 2 \times 2 \times Sin2\theta \times Cos 2\theta$

$I'' = \frac{I_{0}}{2}\times Sin 4\theta$

7 0

3 years ago

Solve these questions plz

8090 [49]

Answer:

For the First answer I cant answer it But I can help you :

The solid has constituent particles tightly packed and the lattice vibrations are carried out by them in their fixed position however oscillations take place about their mean position. These vibrations are increased as soon as there is increase in the temperature which eventually leads to the more chaotic motion of the constituents. At a fixed critical point of temperature, the bonds are broken and the constituent particles are spaced apart changing their phase into liquid. When more temperature is increased by gaining heat energy then the liquid changes into gas where the motion of constituent particles moving freely is dominant.

Explanation:

6 0

2 years ago

A body of mass m, = 0.050 kg and initial velocity v₁ = 9 m / s turned to the right collides with a body of mass m₂ = 0.030 g wit

Ugo [173]

Answer:

Suppose two objects of different masses are moving with different velocities in the same direction on a straght-line before collision. After collision, they stick together and move with common (the same) velocity

6 0

1 year ago

A new ride being built at an amusement park includes a vertical drop of 71.6 meters. Starting from rest the ride vertically drop

AnnyKZ [126]

Answer:

We can conclude 2.3x10^7 J was converted to thermal energy

Explanation:

<u>Energy Conservation </u>

According to the law of conservation of energy, the total energy of an isolated system must be constant. If some kind of energy is 'lost', we know it was transformed into another type.

Let's check the conditions of the problem. The ride vertically drops a distance of 71.6 m starting from rest, and at the bottom of the drop, its speed is 10 m/s. Knowing the mass of the cart plus passengers is 3.5X10^4 kg, we compute the total energy at the top of the drop.

$E=U+K$

Where E is the total energy (which must be conserved) at the top of the drop, U is the gravitational potential energy and K is the kinetic energy. We use the equations for each:

$U=m.g.h$

$\displaystyle K=\frac{mv^2}{2}$

$\displaystyle E=m.g.h+\frac{mv^2}{2}$

At the top, the speed is 0, thus

$\displaystyle E=m.g.h=(35000)(9.8)(71.6)=2.5X10^7\ J$

Now we compute the 'total' energy at the bottom (quoted because we know there is some mechanical energy loss in the drop)

$\displaystyle E'=m.g.h'+\frac{mv'^2}{2}$

This time h'=0 and v=10 m/s, thus

$\displaystyle E'=\frac{(35000)10^2}{2}=1.8x10^6\ J$

The mechanical energy at the top and the bottom are not the same, thus we can know part of it was converted to heat or thermal energy. We compute the difference

$2.5x10^7\ J-1.8x10^6\ J=2.3x10^7\ J$

We can conclude 2.3x10^7 J was converted to thermal energy

4 0

2 years ago

A machine exerts a 100 N force to the right over a 5.00 meter length in 4.00 seconds. Calculate the power output of this machine

Free_Kalibri [48]

500 but I could be wrong go with your gut my dude

6 0

2 years ago

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