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3 years ago

Answer the following questions regarding the equation:

Physics

1 answer:

scoundrel [369]3 years ago

5 0

Explanation:

1) This is a synthesis reaction (two or more reactants combine to form a single product).

2) The coefficients are added to balance the reaction.

3) Adding the states of matter (solid, liquid, gas) will make the reaction more precise.

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Reread the introduction section of this activity. Write a brief conclusion for this activity

ki77a [65]

Answer:

can you write proper

Explanation:

I don't understand

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2 years ago

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Kai swims for the school swim team. He specializes in a backstroke event where he has to swim the 50 m length of the pool three

Westkost [7]

Answer:

Displacement is 50 m

Explanation:

Distance is simply the measurement of the sum of all paths travelled.

Thus, since he swims the 50m length pool 3 times, then the total distance = 50 × 3 = 150 m

Whereas, displacement is the measurement of length of the shortest path from initial point to final point.

In this case initial point to final point is 50m. Thus, the displacement is 50 m

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3 years ago

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The intensity I of light varies inversely as the square of the distance D from the source. If the intensity of illumination on a

emmasim [6.3K]

The intensity on a screen 20 ft from the light will be 0.125-foot candles.

<h3>What is the distance?</h3>

Distance is a numerical representation of the length between two objects or locations.

The intensity I of light varies inversely as the square of the distance D from the source;

I∝(1/D²)

The ratio of the intensity of the two cases;

$\rm \frac{I_1}{I_2} =(\frac{D_2}{D_1} )^2\\\\ \rm \frac{2}{I_2} =(\frac{20}{5} )^2\\\\ \frac{2}{I_2} =4^2 \\\\ I_2= \frac{2}{16} \\\\ I_2= 0.125 \ foot-candles$

Hence, the intensity on a screen 20 ft from the light will be 0.125 foot-candles

To learn more about the distance refer to the link;

brainly.com/question/26711747

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6 0

2 years ago

Physics Help ASAP Please!

balu736 [363]

Answer:

23N

Explanation:

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2 years ago

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Starting at 1.3 m/s, a runner accelerates at a constant 0.22 m/s2 for 6.0 s. What is the runner’s displacement during this time

Anettt [7]

Answer:

answer is 11.76 meter

Explanation:

use 2nd equation of motion

S=ut+1/2at^2

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2 years ago