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mylen [45]
2 years ago
13

A meter stick hurtles through space at a speed of 0. 95c relative to you, with its length perpendicular to the direction of moti

on. You measure its length to be equal to.
Physics
1 answer:
marta [7]2 years ago
6 0

Answer:

Explanation:

Caty  ,  Use   the relativity formula for length.  ( they teach this in H.S. ? )  it's from my Modern Physics in college, A 300 level class  

L = L_{0}\sqrt{1-\frac{v^{2} }{c^{2} } }

L = 3  \sqrt{1-\frac{.95^{2} }{1^{2} } }

L = 0.9367496998  meters

L = 0.94 meters approx

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In an open system, the vapor pressure is equal to the outside air pressure. true false
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PLEASE HELP
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Don't over think it!

For example, if you do 5 laps in 5 minutes then you do one lap per minute. If you use that example and you apply it to your problem you'll notice that the answer is simply C. 1km/min.

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Which statement is true of a piece of ice at 0°C that is put into a freezer at<br> -18°C?
butalik [34]

The statement which is true about a piece of ice at 0°C which is put into a freezer at -18°C is it having the temperature of the freezer.

<h3>What is Temperature?</h3>

This is referred to the degree of hotness or coldness of a body and the unit is Celsius or Kelvin.

The ice at 0°C will experience a change in temperature of the freezer when put in it in this scenario.

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3 0
2 years ago
A length of copper wire carries a current of 11 A, uniformly distributed through its cross section. Calculate the energy density
NISA [10]

Answer:

a)0.983 \frac{J}{m^3}

b)u_E =7.329x10^-3 \frac{J}{m^3}

Explanation:

The energy density is "the energy per unit volume, in the electric field.  The energy stored between the plates of the capacitor equals the energy per unit volume stored in the electric field times the volume between the plates".

A magnetic field is a "vector field that describes the magnetic influence of electric charges in relative motion and magnetized materials".

Part a

For this case we can assume use the equation for the magnetic field in terms of the energy per unit of volume.

B=\sqrt{2\mu_o u}

Where μ0 represent the permeability constant, also known as the magnetic constant. If we solve for u we got:

u=\frac{B^2}{2\mu_o}

We also know that the magnetic field can be expressed in terms of the current and the radius of action R like this:

B=\frac{\mu_o i}{2\pi R}

Replacing this on the formula for u we have:

u=\frac{1}{2\mu_o}(\frac{\mu_o i}{2\pi R})^2

And simplyfing we got:

u=\frac{\mu_o i^2}{8\pi^2 R^2}

Replacing the values given we have:

u=\frac{(4\pix10^{-7} \frac{H}{m} (11A)^2}{8\pi^2 (0.0014m)^2} =0.983 \frac{J}{m^3}

Part b

The density current is given by this formula J=i/A and the resistance by R=\frac{\rho l}{A}

If we use the equation for the energy density we have this:

u_E =\frac{1}{2}\varepsilon_o E^2 =\frac{\varepsilon}{2}(\rho J)^2=\frac{\varepsilon}{2}(\frac{iR}{l})^2

And replacing the values given we have:

u_E =\frac{8.85x10^{-12}\frac{F}{m}}{2}(\frac{11A(3700\frac{\Omega}{m})}{l})^2 =7.329x10^-3 \frac{J}{m^3}

4 0
3 years ago
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