![ln( \frac{m^{5}}{n^{2}})^{3} =3ln( \frac{m^{5}}{n^{2}})= 3(ln({m^{5})-ln({n^{2}))=3(5ln(m)-2ln(n) = 15*ln(m)-6*ln(n) ](https://tex.z-dn.net/?f=ln%28%20%5Cfrac%7Bm%5E%7B5%7D%7D%7Bn%5E%7B2%7D%7D%29%5E%7B3%7D%20%3D3ln%28%20%5Cfrac%7Bm%5E%7B5%7D%7D%7Bn%5E%7B2%7D%7D%29%3D%203%28ln%28%7Bm%5E%7B5%7D%29-ln%28%7Bn%5E%7B2%7D%29%29%3D3%285ln%28m%29-2ln%28n%29%20%3D%2015%2Aln%28m%29-6%2Aln%28n%29%0A%0A)
The answer is 15*ln(m)-6*ln(n)
Answer:
8
Step-by-step explanation:
put 4 in place for a
4=32
dive both sides by 4 and you will get 8
hope this helps
7.4 kg = 74hg = 740dag = 7400g = 74,000 dg = 740,000 cg = 7,400,000 mg
hectograms dekagrams grams decigrams centigrams milligrams
Now which equivalent were you looking for?
Answer:
This equation is equal to y=3/2x-2
Step-by-step explanation:
The awnser is A because you just divid it