Answer:
7.14
Step-by-step explanation:
Let's draw!
H 1 T
HT 2 HT
HTHT 3 HTHT
HTHTHT 4 HTHTHT
HTHTHTHT 5 HTHTHTHT
HTHTHTHTHT 6 HTHTHTHTHT
You can count the probabilities using this.
HHHHTT
HHHTHT
HHTHHT
HHTHTH
HHHTTH
HTHHHT
HTTHHH
HTHTHH
HTHHTH
THHHHT
THHHTH
THHTHH
THTHHH
TTHHHH
Therefore, I think the probability is 14/64. Not sure so check my work.
14 combinations
64 outcomes (2+4+8+16+32+64 or 2^n)
A quadrilatetal with two different pairs of equal and parallel sides.
Answer: The answer is the 3rd one
