Answer:
We are effectively looking for a and b such that 5, a, b, 135 is a geometric sequence.
This sequence has common ratio <span><span>3<span>√<span>1355</span></span></span>=3</span>, hence <span>a=15</span> and <span>b=45</span>
Explanation:
In a geometric sequence, each intermediate term is the geometric mean of the term before it and the term after it.
So we want to find a and b such that 5, a, b, 135 is a geometric sequence.
If the common ratio is r then:
<span><span>a=5r</span><span>b=ar=5<span>r2</span></span><span>135=br=5<span>r3</span></span></span>
Hence <span><span>r3</span>=<span>1355</span>=27</span>, so <span>r=<span>3<span>√27</span></span>=3</span>
Then <span>a=5r=15</span> and <span>b=ar=15⋅3=45</span>
Answer:
x = 8
Step-by-step explanation:
5(x-2)=30
Distribute
5x- 10 = 30
Add 10 to each side
5x-10+10 = 30+10
5x= 40
Divide by 5
5x/5=40/5
x = 8
Answer:
There is no solution
Step-by-step explanation:
The lines never touch each other
Answer:
100 times
Step-by-step explanation:
multiples of 3 on a number cube are 3 and 6
probability of rolling a '3' or '6' is 1/6 + 1/6 = 2/6 or 1/3
1/3 x 300 = 100
Answer:
The weight is 4 pounds :D
Step-by-step explanation:
