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s2008m [1.1K]
3 years ago
6

A matrix a is given. determine if the system ax = b (where x and b have the appropriate number of components) has a solution for

all choices of
b. a = 5 −4 4 2
Mathematics
1 answer:
Alborosie3 years ago
5 0
We can write the system in the following form:
\left[\begin{array}{cccc}5&-4&4&2\end{array}\right]  \left[\begin{array}{c}x_1\\x_2\\x_3\\x_4\end{array}\right]  =b
The above system is equivalent to the following equation:
5x_1-4x_2+4x_3+2x_4=b,\forall b\in\mathbb{R}
Of course, the above system has solution for any values of b since there is one equation and four variable, there is infinite number of solution each time. 
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Write a word problem whose solutions is |20| =20
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manufacturing company produces digital cameras and claim that their products maybe 3% defective. A video company, when purchasin
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Answer:

P(X>17) = 0.979

Step-by-step explanation:

Probability that a camera is defective, p = 3% = 3/100 = 0.03

20 cameras were randomly selected.i.e sample size, n = 20

Probability that a camera is working, q = 1 - p = 1 - 0.03 = 0.97

Probability that more than 17 cameras are working P ( X > 17)

This is a binomial distribution P(X = r) nCr q^{r} p^{n-r}

nCr = \frac{n!}{(n-r)!r!}

P(X>17) = P(X=18) + P(X=19) + P(X=20)

P(X=18) = 20C18 * 0.97^{18} * 0.03^{20-18}

P(X=18) = 20C18 * 0.97^{18} * 0.03^{2}

P(X=18) = 0.0988

P(X=19) = 20C19 * 0.97^{19} * 0.03^{20-19}

P(X=19) = 20C19 * 0.97^{19} * 0.03^{1}

P(X=19) = 0.3364

P(X=20) = 20C20 * 0.97^{20} * 0.03^{20-20}

P(X=20) = 20C20 * 0.97^{20} * 0.03^{0}

P(X=20) = 0.5438

P(X>17) = 0.0988 + 0.3364 + 0.5438

P(X>17) = 0.979

The probability that there are more than 17 working cameras should be 0.979 for the company to accept the whole batch

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3 years ago
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3>-2 i believe
djdjjdksksk sorry i needed more characters
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