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liberstina [14]
3 years ago
14

−2 2 21 +(−0.25÷(− 1 4 )−1.5÷(− 3 16 ))÷(−4 1 11 )

Mathematics
1 answer:
Setler79 [48]3 years ago
6 0

Answer:

-2\frac{2}{21}+(-0.25\div(-14)-1.5\div(-\frac{3}{16}))\div(-4\frac{1}{11})=-4.0551

Step-by-step explanation:

Given : Expression -2\frac{2}{21}+(-0.25\div(-14)-1.5\div(-\frac{3}{16}))\div(-4\frac{1}{11})  

To find : Simplify the expression ?

Solution :

Using BODMAS,

-2\frac{2}{21}+(-0.25\div(-14)-1.5\div(-\frac{3}{16}))\div(-4\frac{1}{11})  

=-\frac{44}{21}+(-0.25\div(-14)-1.5\div(-\frac{3}{16}))\div(-\frac{45}{11})

=-\frac{44}{21}+(\frac{0.25}{14}+\frac{1.5\times 16}{3})\div(-\frac{45}{11})

=-\frac{44}{21}+(\frac{0.25}{14}+\frac{24}{3})\div(-\frac{45}{11})

=-\frac{44}{21}+(\frac{0.25\times 3+24\times 14}{14\times 3})\div(-\frac{45}{11})

=-\frac{44}{21}+(\frac{336.75}{42})\div(-\frac{45}{11})

=-\frac{44}{21}-\frac{336.75\times 11}{42\times 45}

=-\frac{44}{21}-\frac{3704.25}{1890}

=\frac{-44\times 1890-3704.25\times 21}{21\times 1890}

=\frac{-160949.25}{39690}

=−4.0551

Therefore, -2\frac{2}{21}+(-0.25\div(-14)-1.5\div(-\frac{3}{16}))\div(-4\frac{1}{11})=-4.0551

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Paul is two years younger than Patricia. Daniel is 25% older than Patricia. Ten years ago, Daniel was 50% older than Patricia. H
Sergeeva-Olga [200]

We have 3 people: Paul, Daniel and Patricia. Let each name denote that person’s current age in years. Remember that % is the symbol for 1/100.


PAUL: (#A) Paul = Patricia – 2
DANIEL: 
(#B) Daniel = 125% * Patricia = 125 * (1/100) * Patricia = 1.25 * Patricia
(#C) Ten years ago, Daniel’s age at that time would have been Daniel’s current age – 10. IE “Daniel – 10”.
Ten years ago, Patricia’s age at that time would have been Patricia’s current age – 10. IE “Patricia – 10”. 
Ten years ago, Daniel’s age at that time (IE Daniel – 10) was 50% greater than Patricia’s age at the time (Patricia – 10). 
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Daniel – 10 = 150% * (Patricia – 10)
Daniel – 10 = 1.50 * (Patricia – 10)
Daniel – 10 = 1.50 * Patricia – 1.50 * 10
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Daniel = 1.50 * Patricia – 15 + 10
Daniel = 1.50 * Patricia – 5


So now we have 3 equations in 3 unknowns:
(A) Paul = Patricia – 2
(B) Daniel = 1.25 * Patricia
(C) Daniel = 1.50 * Patricia – 5


Solve equations B & C simultaneously
 1.25 * Patricia = 1.50 * Patricia – 5
 1.25 * Patricia – 1.50 * Patricia = – 5
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So now we can write the 3 people’s ages:
(a) Patricia = 20
(b) Paul = Patricia – 2 = 20 – 2 = 18
(c) Daniel = 1.25 * Patricia = 1.25 * 20 = 25

<span>
</span>

<span>Finally, we check our solution against the original question. </span>
Paul is two years younger than Patricia. ……… 20 – 2 = 18 ✔
Daniel is 25% older than Patricia. ……… 25 = 125% * 20 ✔
Ten years ago, Daniel was 50% older than Patricia. 25 – 10 = 150% (20– 10) ✔


Hope that helped :)

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