Question

Please its very urgent :( Name five whole numbers that can be expressed as the difference of two perfect squares. Show the math!

Answer 1

Answer:

9, 17, 3, 1600, 11

Step-by-step explanation:

Difference of two perfect squares:

$a^2-b^2=(a-b)(a+b)$

It seems that you want some

$x=a^2-b^2, x \in \mathbb{Z}_{\ge 0}$

Note: there's no official symbol for the set of whole numbers, I've already seem $\mathbb{W}, \mathbb{Z}^+$, as well.

$5^2-4^2=25-16=9$

There are infinitely many numbers that can satisfy the condition given.

The only condition is that $a\geq b$, once we are considering whole numbers and not integers.

$x_{1}=5^2-4^2=25-16=9$

$x_{2}=9^2-8^2=81-64=17$

$x_{3}=2^2-1^2=4-1=3$

$x_{4}=50^2-30^2=2500-900=1600$

$x_{5}=6^2-5^2=36-25=11$