What is the y-intercept of the graph of the function f(x) = x2 + 3x + 5?

Mathematics

2 answers:

Nitella [24]3 years ago

4 0

Answer:

Step-by-step explanation:

OLga [1]3 years ago

3 0

Hello there!

How do you find the y-intercept?

Answer: To find the y-intercept, substitute in 0 for x and solve for y

y = x² + 3x + 5

y = (0)² + 3(0) + 5

y = 0 + 0 + 5

y = 5

Thus, the correct answer is option D (0,5)

I really hope this answer is clear enough for you to understand. If you have questions about the answer, please let me know.

As always, I'm glad to be your helper this evening~!

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Read 2 more answers

A ladder 16 feet long is leaning against the wall of a tall building. The base of the ladder is moving away from the wall at a r

svet-max [94.6K]

Answer:

a. 0.588

b. 0.0722

c. 4.576 sqft/sec

Step-by-step explanation:

Let b and h denote the base and height as indicated in the diagram. By pythagoras theorem, $h^2 + b^2 = 16^2 = 256 \dotsc\;(1)$ because it is a right angle triangle.

It is given that $\frac{db}{dt} = 1$

Now differentiate (1) with respect to t (time) :

$\displaystyle{2h\frac{dh}{dt} + 2b\frac{db}{dt} = 0 \implies \frac{dh}{dt} = -\frac{b}{h} \frac{db}{dt}}$

$\displaystyle{=-\frac{b}{\sqrt{256 - b^2}} \frac{db}{dt} = -\frac{8}{13.856} \times 1 = -0.588}$

The minus sign indicates that the value of h is actually decreasing. The required answer is 0.588.

b. From the diagram, infer that $16 \sin{\theta} = b$ . When b = 8, then $\theta = \arcsin{0.5} = \ang{30}$ .

Differentiate the above equation w.r.t t

$\displaystyle{16 \cos{\theta} \frac{d\theta}{dt} = \frac{db}{dt} \implies \frac{d\theta}{dt} = \frac{1}{16 \cos{\theta}} = \frac{1}{13.856} = \mathbf{0.0722}}$