Answer:
e. 
Step-by-step explanation:
It is given that,
The density of intergalactic space material is
kg per cubic meter.
And the volume of intergalactic space material is 
So the mass of that much intergalactic space material is,
, where 'm' is the mass, and 'v' is the volume.
Putting the values we get,


It is also given that the mass of lead is the same as the mass of the intergalactic space material. Therefore, the mass of lead is 
So the volume of lead is,


So the volume of lead is
.
Easy
y=a(x-h)^2+k
vertex is (h,k)
we know that vertex is (4,0)
input that point for (h,k)
y=a(x-4)^2+0
y=a(x-4)^2
passes thorugh the point (6,1)
input that point to find a
1=a(6-4)^2
1=a(2)^2
1=a(4)
divide both sides by 4
1/4=a
thefor the equation is
y=(1/4)(x-4)^2
or
y=(1/4)x^2-2x+4
Answer: What do you need help with?
Step-by-step explanation: I can help with anything.
1/10 of 3,000
(1/10)(3000/1)
=(1)(3000)/(10)(1)
=3000/10
=300
Answer:
C, the set of all possible output values
Step-by-step explanation:
Range = Output