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ankoles [38]
4 years ago
15

Need to get the values of each trig function using half angle formulas within the constraint

Mathematics
1 answer:
Marizza181 [45]4 years ago
8 0
\bf cot(u)=4\qquad \pi \ \textless \ u\ \textless \ \frac{3\pi }{2}\implies cot=\cfrac{-4}{-1}\cfrac{\leftarrow adjacent}{\leftarrow opposite}
\\\\\\
hypotenuse\implies \sqrt{(-4)^2+(-1)^2}\implies \sqrt{17}
\\\\\\
cos(\theta )=\cfrac{-4}{\sqrt{17}}\implies \cfrac{-4\sqrt{17}}{17}\\\\
-------------------------------\\\\


\bf sin\left( \frac{u}{2} \right)=\pm\sqrt{\cfrac{1+\frac{4\sqrt{17}}{17}}{2}}\implies \pm\sqrt{\cfrac{\frac{17+4\sqrt{17}}{17}}{2}}\implies \boxed{\pm\sqrt{\cfrac{17+4\sqrt{17}}{34}}}
\\\\\\
cos\left( \frac{u}{2} \right)=\pm\sqrt{\cfrac{1-\frac{4\sqrt{17}}{17}}{2}}\implies \pm\sqrt{\cfrac{\frac{17-4\sqrt{17}}{17}}{2}}\implies \boxed{\pm\sqrt{\cfrac{17-4\sqrt{17}}{34}}}

\bf tan\left( \frac{u}{2} \right)=\pm\sqrt{\cfrac{\frac{17+4\sqrt{17}}{34}}{\frac{17-4\sqrt{17}}{34}}}\implies \boxed{\pm\sqrt{\cfrac{17+4\sqrt{17}}{17-4\sqrt{17}}}}
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The Sydney cricket ground can contain a football field of approximately 147m by 136m. What distance would be covered by walking
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A cylindrical container has a radius of 0.3 meter and a height of 0.75 meter. The container is filled with kerosene. The density
saveliy_v [14]

Answer:

172.83 kg

Step-by-step explanation:

A cylindrical container has a radius (r) of 0.3 meter and a height (h) of 0.75 meter and density of 815 kg/m³.

The density of a substance is the mass per unit volume, it is the ratio of the mass of a substance to the volume occupied. The density is given by the formula:

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The volume of a cylinder is given as:

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6 0
3 years ago
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Nataly [62]

Answer:

m∠BFE  = 171º

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Step-by-step explanation:

∠BFE is supplementary to ∠EFC

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m∠BFE  = 171º

--------------------------

The angle between two chords is equal to half the sum of the intercepted arcs:

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171 = (123 + BE)/2

342 = 123 + BE

219º = BE

6 0
3 years ago
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