First you find the median, the middle term (if there are an even number of terms it is the average of the middle two terms.) Since you have 21 terms, odd, you just use the middle term, in this case 8. The first quartile works the same way, but just on the left half between the start and the median...so the first quartile is 6.
Hello!
Here are some rules to determine the number of significant figures.
- Numbers that are not zero are significant (45 - all are sigfigs)
- Zeros between non-zero digits are significant (3006 → all are sigfigs)
- Trailing zeros are not significant (0.067 → the first two zeros are not sigfigs)
- Trailing zeros after a decimal point are always significant (1.000 → all are sigfigs)
- Trailing zeros in a whole number are not significant (7800 → the last two zeros are not sigfigs)
- In scientific notation, the exponential digits are not significant, known as place holders (6.02 x 10² → 10² is not a sigfig)
Now, let's find the number of significant figures in each given number.
A). 296.54
Since these digits are all <em>non-zero</em>, there are 5 significant figures.
B). 5003.1
Since the two <em>zeros are between non-zero digits</em>, they are significant figures. Thus, there are 5 significant figures.
C). 360.01
Again, the two zeros are between non-zero digits. There are 5 significant figures.
D). 18.3
All of these digits are non-zero, hence, there are 3 significant figures.
Therefore, expression D has the fewest number of significant figures being 3.
2/3 x4 = 8/12
therefore,
They will need 8/12 cup oil
Answer: Its 3 ^(x-2) + 2
Step-by-step explanation:
Because y increases when x increase base is 3. Try
x = 2 gives 3^(-1) + 2 = 2,33 and x = 3 gives 3^0 + 2 = 3