The concentration of a solution of 192 grams dissolved to make 2150 mL of solution is 0.93M. Details about concentration can be found below.
<h3>How to calculate concentration?</h3>
The concentration of a solution can be calculated by dividing the number of moles of the substance by its volume.
no of moles of NH42CO3 = 192g ÷ 96g/mol = 2 mol
Concentration of solution = 2 moles ÷ 2.15L
Concentration of solution = 0.93M
Therefore, the concentration of a solution of 192 grams dissolved to make 2150 mL of solution is 0.93M.
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Answer:
C₂H₂O₃
Explanation:
The empirical formula of a compound is derived bu finding the whole ratios of the constituent elements.
In succinic acid, the ratios of carbon to hydrogen to oxygen is calculated as follows:
<u>% mass</u>
Carbon- 40.60
Hydrogen - 5.18
Oxygen - 54.22
<u>RAM</u>
Carbon -12
Oxygen - 15.994
Hydrogen -1.008
<u>No of moles elements in the compound</u>
Carbon = 40.60/12=3.3833
Oxygen = 54.22/15.994= 3.39
Hydrogen= 5.18/1.008 = 5.1389
Mole ratios of the individual elements we divide by the smallest value of the number of moles.
Carbon: Hydrogen : Oxygen
3.3833/3.3833:3.39/3.3833:5.1389/3.3833
=1:1:1.5
We can multiply the value by 2 to get the whole number ratio.
=2:2:3
The empirical formula will be:
C₂H₂O₃
Answer:
BF₃ ⇒ 0.891
SF₄ ⇒ 0.109
Explanation:
It seems the question is incomplete, in that case I will answer using the values that have been found in simmilar questions online. If the values in your problem vary, keep that in mind when solving it.
" A 9.00 L tank at 23.6 °C is filled with 12.2 g of boron trifluoride gas and 2.37 g of sulfur tetrafluoride gas. You can assume both gases behave as ideal gases under these conditions. Calculate the mole fraction of each gas. Round each of your answers to 3 significant digits. "
First we <u>convert g of both compounds to mol</u>, using their molar mass:
- Boron trifluoride BF₃ ⇒ Molar mass = 67,82 g/mol
12.2 g ÷ 67.82 g/mol = 0.180 mol BF₃
- Sulfur tetrafluoride SF₄ ⇒ Molar mass = 108 g/mol
2.37 g ÷ 108 g/mol = 0.022 mol SF₄
Total number of moles = moles BF₃ + moles SF₄ = 0.180 + 0.022 = 0.202
Finally we calculate the mole fracion of each gas:
- BF₃ ⇒ 0.180 / 0.202 = 0.891
- SF₄ ⇒ 0.022 / 0.202 = 0.109
I believe since #13 (aluminum) is in the 13th row you should 13 neutrons. hope this helps :)