A mole of one element contains Same number of atoms as a mole of another element.
The atomic mass of an element, that is found on the periodic table, may be used to determine the amount of moles in a system. Typically, this mass represents the average of the element's abundant forms found on earth. The mass of an element is given as the average of all of its earthly isotopes. The molar mass of a material is the weight of a mole of that substance. In chemistry, the molar mass is frequently used in converting grams of a chemical to moles. The periodic table lists an element's molar mass, which is its atomic weight in grams per mole (g/mol).
The average mass of an element's atoms expressed in atomic mass units is known as its atomic mass (amu, also known as daltons, D). The weight of the each isotope is combined by its abundance to get the atomic mass, which is a weighted average of all the isotopes of that element.
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I am assuming that the balanced equation is
2H₂ + O₂ ⇒ 2H₂O
Since the hydrogen is the limiting reagent (meaning if the hydrogen runs out the reaction stops), we need to compare the mole ratio between hydrogen and water.
The mole ratio between H₂ and H₂O is 2:2, or 1:1 (as seen on the coefficients of the balanced equation)
And so for every mole of hydrogen, it will be equal to water. Since hydrogen is 4 moles, 4 moles of water would be created.
So we use the coefficients of H₂ and H₂O in order to answer this question.
It would mean that they have the same oxidation number.
Calcium disodium is ionic. When you look at the periodic table, you can see that they are in the same group and that they re both metals. an ionic bond is formed by two or more nonmetals and a covalent bond is formed by two or more nonmetals.
Answer:
Option 1, Cl is reduced and gains electrons
Explanation:
HClO₃ → HClO₂
In HClO₃, chlorine acts with +5 in the oxidation state
In HClO₂,, chlorine acts with +3 in the oxidation state.
The state has been reducted, so the Cl has been reduced. As it was reduced, it means that has won e⁻, in this case 2
Cl⁻⁵ → Cl⁻³ + 2e⁻
