Question

Iron reacts with oxygen gas to produce iron (III) oxide. If there are 52 grams of

Answer 1

Mass of Fe₂O₃ : 74.26 g

Volume of O₂ at STP = 15.624 L

Further explanation

Reaction

4Fe (s) + 3O₂ (g) ==> 2Fe₂O₃ (s)

mol Fe :

Ar Fe = 56 g/mol

$\tt \dfrac{52}{56}=0.93$

mol Fe₂O₃ :

$\tt \dfrac{2}{4}\times 0.93=0.465$

mass Fe₂O₃ :

MW Fe₂O₃ : 159,69 g/mol

$\tt 0.465\times 159,69=74.26~g$

mol O₂ :

$\tt \dfrac{3}{4}\times 0.93=0.6975$

volume O₂ at STP(1 mol=22.4 L)

$\tt 0.6975\times 22.4=15.624~L$