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Salsk061 [2.6K]
3 years ago
12

How do you find range

Mathematics
2 answers:
Tamiku [17]3 years ago
5 0
First order the data from least to greatest, then subtract the smallest value from the largest value in the set.
Ivanshal [37]3 years ago
5 0
Order the numbers from least to greatest. Then subtract the Greater number by the Smaller number.

        Example:
 4, 6, 2, 3, 4, 10, 4, 7
Step One- Order from least to greatest: 2, 3, 4, 4, 4, 7, 10
Step Two- Subtract the Greatest by the Least: 10-2
Answer would be 6. 
(This is just an example. Don't use on answer unless it asks for an example)
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List a positive and negative number whose absolute value is greater than 3. Justify your answer using the number line.
tino4ka555 [31]

Answer:

|5|, |-6|, |4|, |-3.5|...

Step-by-step explanation:

The absolute value is related with the distance between the number and the zero of the number line, then each number greater than 3 will have an absolute value greater than 3, as we can see in the picture, the numbers positive or negative will have a positive distance to the origin of the number line.

5 0
3 years ago
What is the percent equivalent of 11.21? Select one: A. 112.1% B. 0.1121% C. 1,121% D. 11.21%
pogonyaev
It would be 11.21 percent, hope it helps.
5 0
4 years ago
PLEASE HELP DUE TODAYYYY
s2008m [1.1K]
For the second one it should be 12 or -12
8 0
3 years ago
2 and 1/10 divided by 1 and 1/5
dexar [7]

Answer:

The answer is 1 and 3/4

Step-by-step explanation:


8 0
3 years ago
Pls i need this today help me
kondaur [170]

Answer:

Step-by-step explanation:

a) 4x² + 20 = 0

          4x² = -20

            x² = -20/4

            x² = -5 = i² *5

             x = √i²5

            x = i√5

b) 4x² + 5 = -7

        4x² = -7 - 5

       4x² = - 12

          x² = -12/4

         x² = -3 = 3i²

        x = i√3

c) x² + 4x + 20 = 0

a = 1 ; b =4  ; c =20

x = \frac{-b+\sqrt{b^{2}-4ac}}{2a} and \frac{-b-\sqrt{b^{2}-4ac}}{2a};\\\\x = \frac{-4+\sqrt{16-4*1*20}}{2*1} and\frac{-4-\sqrt{16-4*1*20}}{2*1}\\\\=\frac{-4+\sqrt{16-80}}{2}  and \frac{-4-\sqrt{16+80}}{2}\\\\=\frac{-4+\sqrt{-64}}{2}    and  \frac{-4-\sqrt{64}}{2}\\\\= \frac{-4+8i}{2}  and\frac{-4-8}{2}

  = (-2 +4i)  & -12/2

  = (-2 + 4i) and (-6)  

5 0
3 years ago
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