For the answer to the question above, first find out the gradient.
<span>m = rise/run </span>
<span>=(y2-y1)/(x2-x1) </span>
<span>the x's and y's are the points given: "After three hours, the velocity of the car is 53 km/h. After six hours, the velocity of the car is 62 km/h" </span>
<span>(x1,y1) = (3,53) </span>
<span>(x2,y2) = (6,62) </span>
<span>sub values back into the equation </span>
<span>m = (62-53)/(6-3) </span>
<span>m = 9/3 </span>
<span>m = 3 </span>
<span>now we use a point-slope form to find the the standard form </span>
<span>y-y1 = m(x-x1) </span>
<span>where x1 and y1 are any set of point given </span>
<span>y-53 = 3(x-3) </span>
<span>y-53 = 3x - 9 </span>
<span>y = 3x - 9 + 53 </span>
<span>y = 3x + 44 </span>
<span>y is the velocity of the car, x is the time.
</span>I hope this helps.
Answer:
I = 20 i ^ N s
Explanation:
For this problem let's use the Impulse equation
I = Δp = m 
- v₀
The impulse and the velocity are vector quantities, let's calculate on each axis, let's decompose the velocity
cos 60 = vₓ / v
vₓ = v cos 60
sin60 = 
/ v
= v sin60
vₓ = 10 cos 60
= 10 sin60
vₓ = 5.0 m / s
= 8.66 m / s
Let's calculate the impulse on each axis
X axis
Iₓ = m 
- m vₓ₀
How the ball bounces
= - vₓ₀ = vₓ
Iₓ = 2 m vₓ
Iₓ = 2 2 5
Iₓ = 20 N s
Y axis
= m 
- m vyo
On the axis and the ball does not change direction so
= vyo
= 0
The total momentum is
I = Iₓ i ^ + j ^
I = 20 i ^ N s
Answer:
the weight of the wire + 25kg
Explanation:
Answer:
24.3KW
Explanation:
A)The kinetic energy is changing, the potential energy is changing and the chemical energy in form of fuel powering the engine also is changing
The kinetic energy is increasing as the body gain speed, the potential energy also increases as the body gain height against gravity and the chemical energy in form of fuel decreases as the body burn the fuel to create a lifting force
B) The workdone by the lifting force = the change in kinetic energy + the change in potential energy
C)The time taken in seconds to do the work is the variable needed
D) average power generated by the lifting force = (change in kinetic energy + change in potential energy) / time taken in seconds
Average power = 1/2 * m(mass) (Vf-Vi)^2 + mg(hf-hi) /t where vf is final speed and vi is initial speed at rest = 0, similarly, hf = final height and hi = initial height.
Average power = 1/2*810*7^2 + 810*9.81*8.2/3.5s
Average power = (19845+65158.02)/3.5 = 24286.577 approx 24.3kW
