Angular speed must such a cylinder have so that the centripetal acceleration at its surface equals the free-fall acceleration on Earth is 0.0466 rad/s.
Length of the cylinder, L = 9 mi
= (14.5mi)(1609.344 m / 1 mi)
= 23,335.48 m
Diameter of the cylinder, D = 4.78 mi
= (4.78 mi)(1609.344 m / 1 mi)
= 7692.645 m
Radius of the cylinder, r = D / 2
= ( 7692.645 m) / 2
= 3846.32 m
Centripetal acceleration is given by, ac = v^2 / r
We have the relation between linear velocity (v) and the angular velocity(ω) as
v = r ω
Then, ac = v2 / r
= (rω)2 / r
ac = ω^2 r
If the centripetal acceleration is equals the free fall acceleration of earth, then
ω^2 r = g
ω=0.0466 rad/s
- Angular acceleration is the term used to describe the rate of change in angular velocity. If the angular velocity is constant, the angular acceleration is constant.
To know more about angular velocity visit : brainly.com/question/12446100
#SPJ1
Idk can u say it in a another way
Efficiency = Power Output / Power Input
Power Input = Rate of Energy input = 44.4 MJ/kg * 5 kg/h
= 222 MJ/h
But 1 hour = 3600seconds
222 MJ/h = 222 MJ/3600s = 0.061667 MW J/s = Watts
Power input = 0.061667 MW = 61 667 W
From Efficiency = Power Output / Power Input
28% = Power Output / 61667
Power Output = 0.28 * 61667
Power Output = 17266.76 W
Power Output = 17 267 W
Rate of heat Rejection = Power input - Power output
= 61667 - 17267 = 44400 W
Rate of heat Rejection = 44 400 W.
C- Copyright.
Answer:
Vf=3
Explanation:
you must first write your data
data before impact
M1=1000 M2=5000
V1=0 m/s V2 =0m/s
data after impact
M1=1000 M2=5000
V1=15m/s V2=?
M1V1 +M2V2=M1V1 +M2V2f
(1000)(0)+(5000)(0)=(1000)(15)+(5000)Vf
0=15000+5000Vf
- 15000÷5000=5000Vf÷5000
Vf= -3
Vf =3
