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Nataliya [291]
3 years ago
11

A material will float on the surface of a liquid if the material has a density less than that of the liquid. given that the dens

ity of water is approximately 1.0 g/ml, will a block of material having a volume of 1.3 104 in3 and weighing 350 lb float or sink when placed in a reservoir of water?
Physics
1 answer:
Arisa [49]3 years ago
6 0
We will first convert lb to grams and in³ to milliliters. 
350 lb : 2.205 = 158.75733 kg = 158,757.33 grams
1.3 · 10^4 in³ = 13,000 in³ = 13,000 · 0.016387064 = 213.031 liters 
213.031 liters · 1,000 = 213,031 milliliters
Density = m / V = 158,753.33 g / 213,031 ml = 0.7452 g/ ml
Answer: A block of material will float.
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Give the 7 color harmonies​
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Answer:

Complementary colors.

Split complementary colors.

Analogous colors.

Triadic harmonies.

Tetradic harmonies.

Monochromatic harmonies.

Explanation:

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A hurricane sweeps across the ocean and damages the houses of people living along the coast. Which of these does not play any ro
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It is known that birds can detect the earth's magnetic field, but the mechanism of how they do this is not known. It has been su
san4es73 [151]

Answer:

EMF = 5.01 \times 10^{-4} Volts

Explanation:

Here we know that the EMF induced in this Field is given as

EMF = vBL

here B = perpendicular component of magnetic field

v = speed of the bird

L = length of the wings

now we have

B = 5\times 10^{-5} sin40

v = 13 m/s

L = 1.2 m

now we have

EMF = (13)(3.21 \times 10^{-5})(1.2)

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8 0
3 years ago
A tugboat tows a ship at a constant velocity. The tow harness consists of a single tow cable attached to the tugboat at point A
Y_Kistochka [10]

Answer:

The tensions in T_{BC} is approximately 4,934.2 lb and the tension in T_{BD} is approximately  6,035.7 lb

Explanation:

The given information are;

The angle formed by the two rope segments are;

The angle, Φ, formed by rope segment BC with the line AB extended to the center (midpoint) of the ship = 26.0°

The angle, θ, formed by rope segment BD with the line AB extended to the center (midpoint) of the ship = 21.0°

Therefore, we have;

The tension in rope segment BC = T_{BC}

The tension in rope segment BD = T_{BD}

The tension in rope segment AB = T_{AB} = Pulling force of tugboat = 1200 lb

By resolution of forces acting along the line A_F gives;

T_{BC} × cos(26.0°) + T_{BD} × cos(21.0°) = T_{AB} = 1200 lb

T_{BC} × cos(26.0°) + T_{BD} × cos(21.0°) = 1200 lb............(1)

Similarly, we have for equilibrium, the sum of the forces acting perpendicular to tow cable = 0, therefore, we have;

T_{BC} × sin(26.0°) + T_{BD} × sin(21.0°) = 0...........................(2)

Which gives;

T_{BC} × sin(26.0°) = - T_{BD} × sin(21.0°)

T_{BC} = - T_{BD} × sin(21.0°)/(sin(26.0°))  ≈ - T_{BD} × 0.8175

Substituting the value of, T_{BC}, in equation (1), gives;

- T_{BD} × 0.8175 × cos(26.0°) + T_{BD} × cos(21.0°) = 1200 lb

- T_{BD} × 0.7348  + T_{BD} ×0.9336 = 1200 lb

T_{BD} ×0.1988 = 1200 lb

T_{BD} ≈ 1200 lb/0.1988 = 6,035.6938 lb

T_{BD} ≈ 6,035.6938 lb

T_{BC} ≈ - T_{BD} × 0.8175 = 6,035.6938 × 0.8175 = -4934.1733 lb

T_{BC} ≈ -4934.1733 lb

From which we have;

The tensions in T_{BC} ≈ -4934.2 lb and  T_{BD} ≈ 6,035.7 lb.

8 0
3 years ago
Which two components must a vector quantity
Lemur [1.5K]

Answer:

d. Direction and magnitude

Explanation:

The two components of a vector are its magnitude and direction.

Magnitude is the quantity of the substance

Direction is the path.

  • Other quantities are called scalar quantities.
  • Scalar quantities have only magnitude but no direction.

Examples of vector quantities are velocity, displacement, acceleration.

4 0
3 years ago
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