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dlinn [17]
3 years ago
12

Can someone help me with these probability questions?? i want to make sure that i solved these questions right.

Mathematics
1 answer:
kaheart [24]3 years ago
7 0
When you say "I want to make sure that I solved them correctly,
the tasteful, less suspicious thing to do is to list YOUR solutions,
so that the responder can either say "that one's correct" or else
show you how to do it.

1). HHH
HHT
HTH
HTT
THH
THT
TTH
TTT
a).  The probability of each one is 1/8 = 12.5% .
b). There's only one of those on the list.  12.5%
c). 12.5%
d). There are 3 ways that can happen.  3/8 = 0.375 = 37.5%

2). There are 16 possible outcomes.
a). Prob of each outcome is  1/16 = 0.0625  =  6.25% .
b). There's only 1 way that can happen, so it's 6.25% .
c). There's only 1 way that can happen, so it's 6.25% .
d).  There are 6 ways that can happen.  Prob = 6/16 =  37.5%
e). There are 4 ways that can happen.  Prob = 4/16 = 25%
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Answer:

A) R = P/I²

Step-by-step explanation:

I = √P/R

Square each side

I^2 = (√P/R)^2

I^2 = P/R

Multiply each side by R

I^2R =P/R * R

I^2R = P

Divide by I^2

I^2R / I^2 = P/ I^2

R = P/ I^2

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Answer:

a

Step-by-step explanation:

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Answer:

See below

Step-by-step explanation:

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For what value of k does the equation 6(x + 1) + 2 = 3(k5x + 1) + 3 have no solution?
NARA [144]

Answer:

k = (6/15)

Step-by-step explanation:

The equation is:

6*(x + 1) + 2 = 3*(k*5*x + 1) + 3

To have no solutions, we need to have something like:

x + 7 = x + 4

where we can remove x in both sides and end with

7 = 4

So this equation is false, meaning that there is no value of x such that this equation is true, then the equation has no solutions.

First, let's try to simplify our equation:

6*(x + 1) + 2 = 3*(k*5*x + 1) + 3

6*x + 6 + 2 = 3*k*5*x + 3*1 + 3

6*x + 8 = 15*k*x + 6

if 15*k = 6, then the system clerly has no solution.

then:

k = 6/15

then we get:

6*x + 8 = (6/15)*15*x + 6

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8 = 6

The system has no solutions.

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