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vova2212 [387]
3 years ago
6

Describe the transfer of thermal energy as the ice cream melts and as it becomes solid again. In both situations, describe which

objects are gaining and losing energy.
Chemistry
1 answer:
scZoUnD [109]3 years ago
3 0

Answer:

Melting = endothermic, solid = exothermic

Explanation:

Ok so when ice cream melts, that requires heat, so it’s Endothermic. In order to melt it, it requires heat, heat is entering. When it becomes solid again, that is exothermic because it is losing heat in order to become cool again.

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1) emitted energy

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If the ka of a monoprotic weak acid is 5.4 × 10-6, what is the ph of a 0.14 m solution of this acid?
Aleks [24]

pH = 2.1

Let HA (aq) resembles the acid; as a weak acid (a small value of K_{a}) HA would partially dissociate to produce protons H^{+} and A^{-}, its conjugate base. Let the final proton concentration (i.e., [H^{+}]) be x. (Apparently x \ge 0) Construct the following RICE table:

\left\begin{array}{cccccc}\text{R}&HA(aq)&\rightleftharpoons&H^{+}(aq) &+ &A^{-}(aq)\\\text{I} & 0.14 \; \text{M} & &\\\text{C}&-x \; \text{M}& &+x \; \text{M} & & +x \; \text{M}\\E & (0.14 - x)\; \text{M} & & x \; \text{M} & &\+x \; \text{M}\end{array}\right

By definition, (all concentrations are under equilibrium condition)

\left\begin{array}{ccc}K_{a}&=&[H^{+}] \cdot [A^{-}] / [HA]\\&=&x^{2} /(0.14 - x)\end{array}\right

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K_a = 5.4 \cdot 10^{-6}

Equating and simplifying the two expressions gives a quadratic equation; solve the equation for x gives:

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\text{pH} = -\text{ln(}[H^{+}]\text{)} / \text{ln(}10\text{)} = 2.1

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