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const2013 [10]
3 years ago
9

Molar mass CO2 is 44.01 g/mol. How many moles of LiOH are needed to react completely with 25.5 g of CO2?

Chemistry
2 answers:
poizon [28]3 years ago
7 0

Given:

Molar mass CO2 is 44.01 g/mol

25.5 g of CO2

 

Required:

Moles of LiOH

 

Solution:

Balanced equation is:

2LiOH +CO2 → Li2CO3 + H2O

 

25.5g CO2 (1 mole CO2/44.01 g/mol CO2)(2 moles LiOH/1 mol CO2) = 1.16 moles LiOH

joja [24]3 years ago
5 0

Answer:

1.16 moles of LiOH.

Explanation:

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Mercury chloride is a commercial fungicide. If the molar mass is 470 g/mol and the percent composition is 85.0% Hg and 15.0% Cl,
ElenaW [278]
Data: molar mass 470 g/mol

Percent composition:

Hg = 85.0%
Cl = 15.0%

Solution:

1)  Convert % to molar ratios

A. Base: 100 g

=> Hg = 85.0 g / 200.59 g/mol = 0.4235 mol

     Cl = 15.0 g / 35.45 g/mol = 0.4231 mol

B. divide by the higher number and round to whole number

Hg = 0.4325 / 0.4231 = 1.00

Cl = 0.4231 / 0.4231 = 1.00

=> Empirical formula = Hg Cl

2) Find the mass of the empirical formula:

HgCl: 200.59 g/mol + 35.45 g/mol = 236.04

3) Determine how many times is the empirical mass contained in the molecular mass:

470 g/mol / 236.04 = 1.99 ≈ 2

=> Molecular formula = Hg2 Cl2.

Answers:

Empirical formula HgCl
Molecular Formula Hg2Cl2
6 0
3 years ago
Which or these equations is balanced H2SO4 + 2Al > Al2(SO4)3 + H2 or 2KCl + Pb(NO3)2 > 2KNO3 + PbCl2
Dmitry_Shevchenko [17]

Balancing of chemical equation is essential because of the law of conservation of mass, which states that the mass of a system can not be created or removed.

The second equation is balanced

2KCl_(_a_q_) +Pb(NO_3)_2_(_a_q_) ==> 2KNO_3_(-a_q_) + PbCl_2(_a_q_)

This is because the number of elements of each atom in the product side equal the number of elements of each atom on the reactant side.

The first equation is not balanced

H_2SO_4 _(_a_q) + 2Al_(_s_) ==> Al(SO_4)_3_(_a_q_) + H_2_(_g_)

This is because there is 1 molecule of SO_4^{-2} on reactant side as compared to 3 molecules of SO_4^{-2}

To balance the equation we add a coefficient of 3 on sulphuric acid (H_2SO_4) and a coefficient of 3 on hydrogen (H_2)

3H_2SO_4_(_a_q_) + 2Al_(_s_) ==> Al(SO_4)_3_(_a_q_) + 3H_2_(_g_)

7 0
3 years ago
4. Suppose you want to deposit silver on an iron spoon using silver nitrate as
Levart [38]

The spoon should be connected to the negative terminal of the battery. The other electrode should be made of silver.

8 0
2 years ago
What volume of 2.50 M Na2SO4 solution contains 71.0 grams of Na2SO4?
statuscvo [17]

Answer

0.02

Explanation:

7 0
3 years ago
Plz help i need the answer ASAP If 6.20 cm3 of a 6.75 M (M = mol/dm3) solution are diluted to 85.6 cm3 with water, what is the c
Brilliant_brown [7]

Answer:

Option A. 6.75 (6.20/85.6)

Explanation:

The following data were obtained from the question:

Initial volume (V1) = 6.2cm³

Initial concentration (C1) = 6.75M

Final volume (V2) = 85.6cm³

Final concentration (C2) =.?

The final concentration can be obtained by using the dilution formula as show below:

C1V1 = C2V2

6.75 x 6.2 = C2 x 85.6

Divide both side by 85.6

C2 = (6.75 x 6.2) /85.6

C2 = 6.75 (6.2 / 85.6).

6 0
3 years ago
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