Given:
Molar mass CO2 is 44.01 g/mol
25.5 g of CO2
Required:
Moles of LiOH
Solution:
Balanced equation is:
2LiOH +CO2 → Li2CO3 + H2O
25.5g CO2 (1 mole CO2/44.01 g/mol CO2)(2 moles LiOH/1 mol CO2) = 1.16 moles LiOH
Answer:
1.16 moles of LiOH.
Explanation:
D
The temperature.
m=5g
density=1.25g/ml
density=m/v
v=m/density=5/1.25
1. Nitrous Acid
2. Hydroiodic Acid
3. Phosphoric Acid
Just did the lesson