The new concentration of the KCl solution after mixing 1 L new volume is 0.28 M.
<h3>How do we calculate the concentration?</h3>
Concentration in terms of molarity will be calculated by using the below equation as:
M₁V₁ = M₂V₂, where
M₁ = molarity of old KCl solution = 1.6 M
V₁ = volume of old KCl solution = 175 mL = 0.175 L
M₂ = molarity of new KCl solution = ?
V₂ = volume of new KCl solution = 1 L
On putting all these values on the above equation, we get
M₂ = (1.6)(0.175) / (1) = 0.28 M
Hence resultant concentration is 0.28 M.
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Answer:
I think the answer is stored energy
Explanation:
The correct answer is that 1.125 mol of NaOH is available, and 60.75 g of FeCl₃ can be consumed.
The mass of NaOH is 45 g
The molar mass of NaOH = 40 g/mol
The moles of NaOH = mass / molar mass
= 45 / 40
= 1.125
Thus, 1.125 mol NaOH is available
3 NaOH + FeCl₃ ⇒ Fe (OH)₃ + 3NaCl
3 mol of NaOH react with 1 mol of FeCl₃
1.125 moles of NaOH will react with x moles of FeCl₃
x = 1.125 / 3
x = 0.375 mol
0.375 mol FeCl₃ can take part in reaction
The molar mass of FeCl₃ is 162 g/mol
The mass of FeCl₃ = moles × mass
= 0.375 × 162
= 60.75 g
Thus, the amount of FeCl₃, which can be consumed is 60.75 g
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Answer:
The answer is Chemical nomenclature
Explanation:
"IUPAC is best known for its works standardizing nomenclature in chemistry"
