The concentration of the FeSO4 solution in molarity would be 0.4356
The concentration can be derived first by writing out the balanced equation of the reaction:
From the balanced equation: for every 1 mole of KMnO4, 5 moles of FeSO4 is needed for complete oxidation.
Recall that: mole = molarity x volume
Mole of KMnO4 needed = 0.1327 x 0.01642
= 0.002179 mole
1 mole KMnO4 = 5 mole FeSO4
0.002178 mole = 5 x 0.002178/1
= 0.01089 moles of FeSO4
Molarity of FeSO4 = mole/volume
= 0.01089/0.025
= 0.4356 M
More on the calculation of molarity of solutions can be found here: brainly.com/question/16587536
Chlorite is ClO2^-1, and potassium is K with a charge of +1. So, we would write is as KClO2, since the charges cancel out with each other.
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