Answer:
![0.22 -1 *0.029 =0.191](https://tex.z-dn.net/?f=%200.22%20-1%20%2A0.029%20%3D0.191)
![0.22 +1 *0.029 =0.249](https://tex.z-dn.net/?f=%200.22%20%2B1%20%2A0.029%20%3D0.249)
And the best option would be:
D. (0.191 to 0.249)
Step-by-step explanation:
For this case we know that the mean is:
![\bar X = 0.22](https://tex.z-dn.net/?f=%5Cbar%20X%20%3D%200.22)
And the standard error is given by:
![SE = 0.029](https://tex.z-dn.net/?f=%20SE%20%3D%200.029)
We want to construct a 68% confidence interval so then the significance level would be :
and
. The confidence interval is given by:
![\bar X \pm z_{\alpha/2} SE](https://tex.z-dn.net/?f=%20%5Cbar%20X%20%5Cpm%20z_%7B%5Calpha%2F2%7D%20SE)
Now we can find the critical value using the normal standard distribution and we got looking for a quantile who accumulate 0.16 of the area on each tail and we got:
![z_{\alpha/2}= 1](https://tex.z-dn.net/?f=%20z_%7B%5Calpha%2F2%7D%3D%201)
And replacing we got:
![0.22 -1 *0.029 =0.191](https://tex.z-dn.net/?f=%200.22%20-1%20%2A0.029%20%3D0.191)
![0.22 +1 *0.029 =0.249](https://tex.z-dn.net/?f=%200.22%20%2B1%20%2A0.029%20%3D0.249)
And the best option would be:
D. (0.191 to 0.249)
60 months is 5 years
12 × 5 = 60
Interest = Principle amount × Rate × Time in years
= 650 × 0.06 × 5 (6% =
![\frac{6}{100}](https://tex.z-dn.net/?f=%20%5Cfrac%7B6%7D%7B100%7D%20)
= 0.06)
= R195
R650 + R195 =
R845
Answer:
-6X+10
Step-by-step explanation:
First one is 40 cube square and the second one is 125 cube square.
I hope this helps you
x= -1
g (-1)= -1+3=2
f (g (-1))=f (2)=?
x=2
f (2)=3.2^2+1
f (2)=3.4+1
f (2)=12+1
f (2)=13