1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
denpristay [2]
2 years ago
9

What is 5,403.264 rounded to the nearest hundred

Mathematics
2 answers:
mihalych1998 [28]2 years ago
7 0
5,403.26 this is because after the first place after the decimal is the tenth line, the second place is the hundredth line and the third place is the thousandth line
Likurg_2 [28]2 years ago
6 0
The answer is 5400.000. Hope this helps.
You might be interested in
Find the general solution for cos x = 0, where n is an integer.
Romashka-Z-Leto [24]
First we solve this equation:
x = cos^-1(0) = pi/2 and 3pi/2

Now, this is the answer for angles between 0 and 2pi

but there are "negative angles" and angles larger than 2pi
so the general solution that includes all of these cases is:

x = pi/2 + n*pi

here n is any integer.
6 0
3 years ago
What is the image of -1 - 5 after a dilation by a scale factor of 5 centered at the origin
amm1812

the Given data

*The given point is (-1, -5)

*The given scale factor is 5

The image of -1 - 5 after dilation by a scale factor of 5 centered at the origin ​is given as

(-1,-5)=(-1\times5,-5\times5)=(-5,-25)

Thus, the image after dilation by a scale factor of 5 centered at origin is (-5, -25)

6 0
1 year ago
the football team has 4 freshman, 7 sophomores, 10 juniors, and 15 seniors. two players will be chosen at random to participate
Anit [1.1K]
This answer would have to be snakskeewhsof ndxjssoaanshew
4 0
3 years ago
4> Solve by using Laplace transform: y'+5y'+4y=0; y(0)=3 y'(o)=o
harina [27]

Answer:

y=3e^{-4t}

Step-by-step explanation:

y''+5y'+4y=0

Applying the Laplace transform:

\mathcal{L}[y'']+5\mathcal{L}[y']+4\mathcal{L}[y']=0

With the formulas:

\mathcal{L}[y'']=s^2\mathcal{L}[y]-y(0)s-y'(0)

\mathcal{L}[y']=s\mathcal{L}[y]-y(0)

\mathcal{L}[x]=L

s^2L-3s+5sL-3+4L=0

Solving for L

L(s^2+5s+4)=3s+3

L=\frac{3s+3}{s^2+5s+4}

L=\frac{3(s+1)}{(s+1)(s+4)}

L=\frac3{s+4}

Apply the inverse Laplace transform with this formula:

\mathcal{L}^{-1}[\frac1{s-a}]=e^{at}

y=3\mathcal{L}^{-1}[\frac1{s+4}]=3e^{-4t}

7 0
2 years ago
The measures of the angles of a triangle solve for X
kompoz [17]

Answer:

x = 7

Step-by-step explanation:

Because this is a right triangle, one angle is a right angle (90°). All triangles have all three angle measures adding up to 180°, so the other two angles' measures add up to 90° (90 + 90 = 180).

Combine like terms of the angle measures.

6x + 9x = 15x

-3 + (-12) = -15

15x - 15

Because the sum of the measures of the two angles have to equal 90,

15x - 15 = 90

Add 15 from both sides.

15x = 105

Divide both sides by 15.

x = 7

To check, substitute 7 in both expressions.

6(7) - 3 = 39

9(7) - 12 = 51

39 + 51 + 90 (the measure of the right angle) = 180, so the value of x is 7.

I hope this helped :)

7 0
3 years ago
Other questions:
  • 100 text books increased by 99 percent
    13·2 answers
  • PLEASE ANSWER FAST!!!!
    7·1 answer
  • What is the solution set of the quadratic inequality x^2+x-2>=0?
    6·1 answer
  • What is an isosceles scalene and equadrilateral triangle
    7·2 answers
  • Cual es la ecuación de la recta que pasa por el punto (1, 2) y tiene una inclinación de 71.56505118
    10·1 answer
  • The altitude of an equilateral triangle is 7 units long. The length of one side of the triangle is ____ units.
    13·2 answers
  • One floor of a dollhouse is 1.6 feet tall. The dollhouse contains two levels of living areas and an attic for a total of 2.5 flo
    8·2 answers
  • I need help ASAP it’s the one with the distributive property
    8·1 answer
  • Find the equation of the line shown.
    10·1 answer
  • What is the slope of the line containing (-2,5) and (4, -4)?
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!