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olganol [36]
4 years ago
9

What is the correct label for a solution?

Physics
1 answer:
svetoff [14.1K]4 years ago
8 0
<span>a homogenous mixture</span>
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Answer each question yes or no. Assume the motions and currents mentioned are along the x axis and fields are in the y direction
Sergeeva-Olga [200]

(a)  Does an electric field exert a force on a stationary charged object? YES ( F = Eq)

(b)  Does a magnetic field do so?- NO ( F= qvB)  

(c)   Does an electric field exert a force on a moving charged object? YES

(d) Does a magnetic field do so? YES ( F = qvB)  

(e) Does an electric field exert a force on a straight current-carrying wire? (  NO)

(f) Does a magnetic field do so? Yes

(g) Does an electric field exert a force on a beam of moving electrons?          Yes  

(h) Does a magnetic field do so?    YeS

To know more about magnetic field    visit : brainly.com/question/10353944

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6 0
2 years ago
Young's experiment is performed with light of wavelength 502 nm from excited helium atoms. Fringes are measured carefully on a s
jok3333 [9.3K]

Answer:

0.88 mm

Explanation:

Given

Wavelength of the atoms, λ = 502 nm = 502*10^-9 m

Radius of the screen away from the double slit, r = 1 m

We know that Y(20) = 11.4*10^-3 m

d = (20 * R * λ) / Y(20)

d = (20 * 1 * 502*10^-9)/11.4*10^-3

d = 1*10^-5 / 11.4*10^-3

d = 0.88 mm

Therefore, the distance of separation between the two slits is 0.88 mm

7 0
4 years ago
What is the net force on the purple ring in the picture above. _________
Dmitrij [34]

Answer:

equal

Explanation:

Because of Newton's third law

8 0
3 years ago
An object with a resistance of 28 Ω has 76 V applied to it. How much electric current is going through this object? Answer in un
12345 [234]

Answer : The electric current of a circuit is, 2.8 A.

Explanation :

Using Ohm's law :

V=I\times R

Or,

I=\frac{V}{R}

where,

R = resistance of a circuit = 28 Ω

V = voltage of circuit = 76 volts = 76 V

I = current flowing in a circuit = ?

Now put all the given values in the above formula, we get :

I=\frac{V}{R}

I=\frac{76V}{28\Omega }

I=2.8A

Therefore, the electric current of a circuit is, 2.8 A

5 0
3 years ago
If I measure the current to be 0.5 A and the voltage is 4.5 V. What is my Power?
Korvikt [17]
As we know that P=IV so P = (0.5A)(4.5V)
                                            P= 2.25 watt
6 0
3 years ago
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