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3 years ago

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Besides providing food and lumber, some trees are valuable natural resources because they contain substances that help make ____

_. A. ore B. medicines C. petroleum D. silicon wafers

2 answers:

kondaur [170]3 years ago

6 0

Medicines would be your answer

antiseptic1488 [7]3 years ago

4 0

The correct answer is B. Medicines

Explanation:

Trees are valuable natural resources used to obtain food through edible fruits, roots, etc and also to obtain lumber that is used to build structures, furniture, among others. Besides this, trees are valuable because it is possible to obtain medicinal substances from these. For example, willow bark can be used to treat fever, and pain because the substance in it acts similarly to aspirin. This makes thousand of tree species to be used in the process of creating medicines. Thus, besides food and lumber trees provided substances that help make medicines.

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In 2017, the company SpaceX became the first private company to send supplies to the International Space Station with a reusable

pav-90 [236]

Answer:

Approximately $3.98\; \rm m \cdot s^{-2}$ .

Assumption: air resistance on the rocket is negligible. Take $g = \rm 9.81\; m \cdot s^{-2}$ .

Explanation:

By Newton's Second Law of Motion, the acceleration of the rocket is proportional to the net force on it.

$\displaystyle \text{Acceleration} = \frac{\text{Net Force}}{\text{Mass}}$ .

Note that in this case, the uppercase letter $\rm M$ in the units stands for "mega-", which is the same as $10^6$ times the unit that follows. For example, $\rm 1\; Mg = 10^6\; g$ , while $\rm 1\; MN = 10^6\; N$ .

Convert the mass of the rocket and the thrust of its engines to SI standard units:

The standard unit for mass is kilograms: $\displaystyle m = \rm 552\; Mg = 552 \times 10^6\; g \times \frac{1\; \rm kg}{10^3\; g} = 552 \times 10^3 \; kg$ .
The standard for forces (including thrust) is Newtons: $\text{Thrust} = \rm 7.61 \; MN = 7.61 \times 10^6\; N$ .

At launch, the velocity of the rocket would be pretty low. Hence, compared to thrust and weight, the air resistance on the rocket would be pretty negligible. The two main forces that contribute to the net force of the rocket would be:

Thrust (which is supposed to go upwards), and
Weight (downwards due to gravity.)

The thrust on the rocket is already known to be $\rm 7.61 \times 10^6\; N$ . Since the rocket is quite close to the ground, the gravitational acceleration on it should be approximately $9.81\; \rm m \cdot s^{-2} = 9.81 \; N \cdot kg^{-1}$ . Hence, the weight on the rocket would be approximately $9.81\; \rm N \cdot kg^{-1} \times 552 \times 10^3\; kg = 5.41412\times 10^6\; N$ .

The magnitude of the net force on the rocket would be

$\begin{aligned}&\text{Thrust} - \text{Weight} \\ &= 7.61 \times 10^6\; \rm N - 5.41412\times 10^6\; N \\ &\approx 2.19 \times 10^6\; \rm N\end{aligned}$ .

Apply the formula $\displaystyle \text{Acceleration} = \frac{\text{Net Force}}{\text{Mass}}$ to find the net force on the rocket. To make sure that the output (acceleration) is in SI units (meters-per-second,) make sure that the inputs (net force and mass) are also in SI units (Newtons for net force and kilograms for mass.)

$\begin{aligned}\displaystyle &\text{Acceleration} \\ &= \frac{\text{Net Force}}{\text{Mass}} \\ &= \frac{2.19 \times 10^6\; \rm N}{552 \times 10^3\; \rm kg} \\ &\approx \rm 3.98\; \rm m \cdot s^{-2}\end{aligned}$ .

6 0

3 years ago

Question in picture.

Gelneren [198K]

<h2>Hello!</h2>

The answer is: A. 19.3 joules

<h2>Why?</h2>

Since it's an elastic collision, the kinetic energy after and before the collision will be the same.

Kinetic energy can be calculated using the following equation:

$KE=\frac{1}{2}mv^{2}$

Where:

$KE=KineticEnergy\\m=mass\\v=velocity$

So,

First object, (going to the right):

$m=7.20kg\\v=2\frac{m}{s}$

$KE_{1}=\frac{1}{2}*7.20Kg*(2\frac{m}{s})^{2}=14.4Joules$

Second object:, (going to the left):

$m=5.75kg\\v=-1.30\frac{m}{s}$

$KE_{2}=\frac{1}{2}*5.75kg*(-1.30\frac{m}{s})^{2}=4.86Joules$

Remember,

$1Joule=1Kg.\frac{m^{2}}{s^{2} }$

Hence,

The total kinetic energy after the collision will be:

$T=KE_{1}+KE_{2}=14.4Joules+4.86joules=19.26joules=19.3joules$

The total kinetic energy after the collision is 19.3 joules (rounded to the nearest tenth)

Have a nice day!

6 0

3 years ago

Why did Galileo use a thought experiment instead of working with real objects

Alja [10]

Answer:

Galileo thought that a ball, rolling or sliding down a hill without friction, would run up to the same height on an opposite hill.

Suppose that the opposite hill was horizontal. Would the ball's motion continue forever along the tangent, or forever parallel to the Earth's surface

Galileo's conclusion from this thought experiment was that no force is needed to keep an object moving with constant velocity.

Newton took this as his first law of motion.

Explanation:

Here ya go-

5 0

3 years ago

If an object stays still or continues to move at the same speed and in the same direction, what type of force is acting on it?

Nitella [24]

Movement force or something

4 0

3 years ago

a student weighs 1200N they are standing in an elevator that is moving downwards at a constant speed of

baherus [9]

Answer:

<em>Elevator That Is Moving Downwards At A Constant Speed Of 4.9 M/S. What Is The Magnitude Of The Net Force Acing On The Student?</em>

<em>This problem has been solved!</em>

<em>This problem has been solved!See the answer</em>

<em>This problem has been solved!See the answerA student weighs 1200N. They are standing in an elevator that is moving downwards at a constant speed of </em><em>4.9 m/s. What is the magnitude of the net force acing on the student?</em>

6 0

3 years ago

Read 2 more answers