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nata0808 [166]
3 years ago
9

What is the value of -6x3-y2-3xy if x=-2 and y=4

Mathematics
2 answers:
Svetach [21]3 years ago
5 0
<h2>Hello!</h2>

The answer is:

The value of the given expression evaluated with x equals to -2 and y equals to 4, is equal to 56 units.

<h2>Why?</h2>

To solve the problem, we need to evaluate both variables for the given values:

x=-2

and

y=4

So, we are given the expression:

-6x^{3}-y^{2}-3xy

Then, evaluating the given values for both variables, we have:

-6*(-2)^{3}-(4)^{2}-3*(-2)*(4)=(-6*-8)-(16)+24=48-16+24=56

Hence, we have that the answer is:

The value of the given expression evaluated with x equals to -2 and y equals to 4, is equal to 56 units.

Have a nice day!

Delicious77 [7]3 years ago
4 0

Answer:

The value of given expression = 56

Step-by-step explanation:

It is given an expression in variable x and y

-6x³ - y² - 3xy

<u>To find the value of given expression</u>

Let expression be,

-6x³ - y² - 3xy

When x = -2 and y =4

-6x³ - y² - 3xy = -6(-2)³ - 4² - (3 * -2 * 4)

 = -6*-8 - 16 + 24

 = 48 - 16 + 24

 = 56

Therefore the value of given expression is 56

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