Answer: yes
Step-by-step explanation:
Add (11/2)^2 to both sides
x^2 + 11x + (11/2)^2 = 3 + (11/2)^2
x^2 + 11x + (11/2)^2 = 133/4
(x + 11/2)^2 = 133/4
x + 11/2 = sqrt of (133/4)
Solutions are
x = (sqrt of (133) - 11))/2
x = (-sqrt of (133) -11))/2
If y = x^2 + 2x and y = 3x + 20
<span>Then </span>
<span>x^2 + 2x = 3x + 20 </span>
<span>x^2 - x - 20 = 0 </span>
<span>(x - 5)(x + 4) = 0 </span>
<span>x = 5, - 4 </span>
<span>For x = 5, y = 3(5) + 20 = 35 </span>
<span>For x = - 4, y = 3(-4) + 20 = 8 </span>
<span>(5, 35), (-4, 8)</span>
First find the area of the rectangle.
Area of Rectangle= Lenght×Width
Area of Rectangle=10×5
Area of Rectangle =50cm^2
Then you find the area of the triangle.
Area of Triangle= Length×Height
Area of Triangle=8×5
Area of Triangle=40cm^2
Add the two areas to find the area of the whole figure.
50 + 40 = 90cm^2
