Can someone tell me what’s the answer?

Assume that a sample is used to estimate a population proportion p. Find the 99% confidence interval for a sample of size 229 wi

meriva

Answer:

A. 99% CI for p: 0.125 < p < 0.259

B. 99% CI for p: 0.807 < p < 0.911

C. 95% CI for p: 0.776 < p < 0.844

D. 95% CI using t-distribution: 23.7 < µ < 40.3

Step-by-step explanation:

A.

$p=\frac{x}{n} =\frac{44}{229} = 0.192139738$

Confidence = 99% = 0.99

$\alpha$ =1 - confidence = 1 - 0.99 = 0.01

Critical z-value = $z_{\alpha/2}=z_{0.01/2}=z_{0.005}=2.58$ (from z-table)

SE = Standard Error of p

$SE=\sqrt{\frac{p(1-p)}{n} }$

$SE=\sqrt{\frac{0.192139738(1-0.192139738)}{229} }$

$SE=\sqrt{\frac{0.155222059}{229} }$

SE = 0.026035

E = Margin of Error

E = z-value * SE = 2.58 * 0.026035

E = 0.067170516

Lower Limit = p - E = 0.192139738 - 0.067170516 = 0.125

Upper Limit = p + E = 0.192139738 + 0.067170516 = 0.259

99% CI for p: 0.125 < p < 0.259

B.

$p=\frac{x}{n} =\frac{256}{298} = 0.8590604$

Confidence = 99% = 0.99

$\alpha$ =1 - confidence = 1 - 0.99 = 0.01

Critical z-value = $z_{\alpha/2}=z_{0.01/2}=z_{0.005}=2.58$ (from z-table)

SE = Standard Error of p

$SE=\sqrt{\frac{p(1-p)}{n} }$

$SE=\sqrt{\frac{0.8590604(1-0.8590604)}{298} }$

$SE=\sqrt{\frac{0.121075629}{298} }$

SE = 0.020157

E = Margin of Error

E = z-value * SE = 2.58 * 0.020157

E = 0.052004

Lower Limit = p - E = 0.8590604 - 0.052004 = 0.807

Upper Limit = p + E = 0.8590604 + 0.052004 = 0.911

99% CI for p: 0.125 < p < 0.259

C.

$p=\frac{x}{n} =\frac{405}{500} = 0.81$

Confidence = 95% = 0.95

$\alpha$ =1 - confidence = 1 - 0.95 = 0.05

Critical z-value = $z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$ (from z-table)

SE = Standard Error of p

$SE=\sqrt{\frac{p(1-p)}{n} }$

$SE=\sqrt{\frac{0.81(1-0.81)}{500} }$

$SE=\sqrt{\frac{0.1539}{500} }$

SE = 0.017544

E = Margin of Error

E = z-value * SE = 1.96 * 0.017544

E = 0.034387

Lower Limit = p - E = 0.81 - 0.034387 = 0.776

Upper Limit = p + E = 0.81 + 0.034387 = 0.844

95% CI for p: 0.776 < p < 0.844

D.

x = sample mean = 32

s = sample standard deviation = 13

n = sample size = 12

Confidence = 95% = 0.95

$\alpha$ =1 - confidence = 1 - 0.95 = 0.05

Being the sample size less than 30, we use the statistical t.

df = degree of freedom = n - 1 = 12 - 1 = 11

Critical t-value = $t_{\alpha/2,df}=t_{0.05/2,11}=t_{0.025,11}=2.201$ (from t-table, two tails, df=11)

SE = standard error

$SE=\frac{s_{x} }{\sqrt{n} } =\frac{13 }{\sqrt{12} }=3.752777$

E = margin of error

E = t-value * SE = 2.201 * 3.752777 = 8.259862

Lower Limit = x - E = 32 - 8.259862 = 23.7

Upper Limit = x + E = 32 + 8.259862 = 40.3

95% CI using t-distribution: 23.7 < µ < 40.3

Hope this helps!

4 0

3 years ago

I need help please!:D

notsponge [240]

Answer:

176 R. 5

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Tonisha has a lemonade stand. She has$26 in expenses and wants to make at least $73 per day.

oksian1 [2.3K]

Answer:

x - 26 ≥ 73

Step-by-step explanation:

x is the total sum of money earned. To find the answer, you need to subtract 26 from x because that's the amount of her expenses. It also has to be either greater than or equal to 73 because she wants to make at least $73 per day.

Can you give me brainliest please?

3 0

3 years ago

Cesar has 32 boxes of pasta and 48 jars of sauce that he will be putting into bags for a food drive. He wants each bag to have t

zhannawk [14.2K]

Cesar has 32 boxes of pasta and 48 jars of sauce that he will be putting into bags for a food drive. He wants each bag to have the same amount of pasta and sauce and wants to use all of the items. Use the drop-down menus to complete the statements below about the number of bags Cesar can make.

What is the greatest number of bags Cesar can make and Each bag would have _____ pasta and _____ jars of sauce

Answer:

The greatest number of bags Cesar can make is 16 bags.

Each bag would have 2 pasta and 3 of jars of sauce

Step-by-step explanation:

We solve the above question using Greatest Common Factor method

The factors of 32 are: 1, 2, 4, 8, 16, 32

The factors of 48 are: 1, 2, 3, 4, 6, 8, 12, 16, 24, 48

Then the greatest common factor is 16.

Hence, the greatest number of bags Cesar can make is 16 bags.

For Pasta, We have 32 pasta

Each bag would have: 32/16

= 2 pasta

For Jars of sauce, we have 48 jars of sauce.= 48/16

= 3 jars of sauce

4 0

3 years ago

I’LL GIVE YA BRAINLESS!! I need the answer ASAP

Lady_Fox [76]

Answer: The answers are 20% and 40%

Step-by-step explanation:

Cost price is $240,000

The percentage of $48000 will be

(48000/240000) × 100

= 20%

The percentage of $96000 will be

(96000/240000) ×100

= 40%

4 0

3 years ago