Answer:
Acceleration of the box is 4.9 m/s².
Explanation:
The free body diagram is shown below.
The weight of the body can be resolved into two mutually perpendicular components as shown. The force responsible for sliding motion of the box along the incline is due to 
acting along the incline.
Therefore, as per Newton's second law of motion,
Net force = 
Now, net force acting along the incline is only
Therefore,
Now, 
Therefore, the acceleration of the box is given as:
Acceleration of the box is 4.9 m/s².
Answer:
Length (l) = 6 m
height (h) = 3 m
Load(L) = 500 N
Effort (E) = ?
we know the principal that
E * l = L * h
6 E = 500 * 3
6E = 1500
E = 250
therefore 250 N work is done on the barrel.
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I hope my answer has come to your help. God bless and have a nice day ahead!
The final velocity before takeoff is 104.96 m / s.
<u>Explanation:</u>
The last velocity of a given object over some time defines the final velocity. The final velocity of the object is given by the product of acceleration and time and adding this product to the initial velocity.
To calculate the final velocity,
V = u + at
where v represents the final velocity,
u represents the initial velocity,
a represents the acceleration
t represents the time taken.
v = 104.96 m / s.
The answer to this question is true.
