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Ilya [14]
4 years ago
8

You set up an experiment to determine the conditions needed to form the gemstones with the most clarity. You gather data from 5

different mines located around the globe, making sure to choose locations that have similar underground temperatures but different soil compositions. You discover that the minerals in the water in these locations is what determines gem clarity, Identify the independent, dependent, and controlled variables in this experiment below. 1.What is the independent variable in this experiment? * 2.What is the dependent variable in this experiment? * 3.What is the controlled variable in this experiment? i really need help
Chemistry
2 answers:
natima [27]4 years ago
8 0
Can u help me plss no one is helping me :(
Andreyy894 years ago
6 0
I’m in chemistry too. Giving this my best guess I’d say
Independent: Gem Mines
Dependent: Gem clarity
Controlled: Temperature
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What is the mass in grams of 7.5 x 10^15 atoms of nickel, Ni?
statuscvo [17]
<h3>Answer:</h3>

7.3 × 10⁻⁷ g Ni

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3>Explanation:</h3>

<u>Step 1: Define</u>

7.5 × 10¹⁵ atoms Ni

<u>Step 2: Identify Conversions</u>

Avogadro's Number

Molar Mass of Ni - 58.69 g/mol

<u>Step 3: Convert</u>

  1. Set up:                              \displaystyle 7.5 \cdot 10^{15} \ atoms \ Ni(\frac{1 \ mol \ Ni}{6.022 \cdot 10^{23} \ atoms \ Ni})(\frac{58.69 \ g \ Ni}{1 \ mol \ Ni})
  2. Multiply:                                                                                                           \displaystyle 7.30945 \cdot 10^{-7} \ g \ Ni

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

7.30945 × 10⁻⁷ g Ni ≈ 7.3 × 10⁻⁷ g Ni

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