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OleMash [197]
4 years ago
5

Which of the following statements is not true for an exothermic reaction? Question options: The products have a higher heat cont

ent than the reactants. The temperature of the reaction system increases. The temperature of the surroundings increases. Heat passes from the reaction system to the surroundings. The enthalpy change for the reaction is negativ
Chemistry
1 answer:
dsp734 years ago
5 0

Answer:

The products have a higher heat content than the reactants.

Explanation:

The statement above is not true for an exothermic reaction because in an exothermic reaction heat is released to the surroundings. This simply means that the total energy of the products is less than that of the reactants.

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How is the temperature of the Earth's atmosphere linked to the<br> concentration of carbon dioxide?
Anni [7]

Answer:

the amount of carbon dioxide controls the earths temperature

Explanation:

that is why global warming is a problem because the more carbon dioxide produced the hotter earth gets

7 0
4 years ago
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5.
SIZIF [17.4K]

Answer:

The term reduction means you are reducing the componenets of the air.

Explanation:

8 0
3 years ago
URGENT!!!What volume of a 0.88 M solution can be made using 130. Grams of FeCI^2?
Likurg_2 [28]

Answer:

1.16L can be made

Explanation:

Molarity = Mol / Volume

Volume = Mol / Molarity

Let's determine the moles of salt, with that mass:

130 g FeCl₂ . 1mol / 126.75 g = 1.02 moles of FeCl₂

Volume = 1.02 mol / 0.88 mol/L → 1.16L

5 0
3 years ago
the volume of a cylindrical tin can with a top and a bottom is to be 16Ï cubic inches. if a minimum amount of tin is to be used
Hunter-Best [27]

Answer:

The required height of the tin can is given by the height at the minimum value of the surface area function of the tin can

The height of the tin can must be 4 inches

Reason:

The given information on the tin can are;

Volume of the tin can = 16·π in.³

The amount of tin to be used = Minimum amount

The height of the can in inches required

Solution;

Let h, represent the height of the can, we have;

The surface area of the can, S.A. = 2·π·r² + 2·π·r·h

The volume of the can, V = π·r²·h

Where;

r = The radius of the tin can

h = The height of the tin can

Which gives;

16·π = π·r²·h

16 = r²·h

Which gives;

When the minimum amount of tin is used, we have;

Therefore;

4·π·(r³ - 8) = r² × 0

r³ = 8

r = 2

The radius of the tin can, r = 2 inches

The

The height of the tin can, h = 4 inches

Learn more here:

brainly.com/question/14316282

Explanation:

8 0
3 years ago
Enter your answer in the provided box.S(rhombic) + O2(g) → SO2(g) ΔHo rxn= −296.06 kJ/molS(monoclinic) + O2(g) → SO2(g) ΔHo rxn=
IgorC [24]

Answer: \Delta H^0=+0.3kJ/mol.

Explanation:

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

S_{rhombic}+O_2(g)\rightarrow SO_2(g)    \Delta H^0_1=-296.06kJ   (1)

S_{monoclinic}+O_2(g)\rightarrow SO_2(g)/tex] [tex]\Delta H^0_2=-296.36kJ  (2)

The final reaction is:  

S_{rhombic}\rightarrow S_{monoclinic}  \Delta H^0_3=?   (3)

By subtracting (1) and (2)

\Delta H^0_3=\Delta H^0_1-\Delta H^0_2=-296.06kJ-(-296.36kJ)=0.3kJ

Hence the enthalpy change for the transformation S(rhombic) → S(monoclinic) is 0.3kJ

3 0
3 years ago
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