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kvasek [131]
2 years ago
5

A carpenter lays 18 square feet of tiles in 2/3 of an hour. How many square feet of tile does the carpenter lay per hour?

Mathematics
1 answer:
Zarrin [17]2 years ago
8 0

Answer:

D. 27 square feet per hour

Step-by-step explanation:

Step 1:

Find the unit rate. Since 18 tiles are per 2/3 of an hour, we can divide 18 by 2 to get 9 tiles layed per third hour.

Step 2:

Multiply the 9 per third of an hour by 3 to find how many are per hour,

9*3=27 square feet per hour


This is called finding the unit rate of a scenario.

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mojhsa [17]
Your Right Answer is A good luck
5 0
3 years ago
Factorise the following.<br> 49g^2 - 36h^2 - 28g - 24h
vagabundo [1.1K]

Answer:  -4(7g - 6h)(7g + 6h)

<u>Step-by-step explanation:</u>

Separate the 4 terms into two groups of 2 terms. Then factor out the GCF of each group. You should end up with a common factor in each group - that is one of the factors.  The other factor is what you factored out from each term.

  49g² - 36h²              - 28g - 24h

(7g - 6h)(<u>7g + 6h</u>)          -4(<u>7g + 6h</u>)

They both have a common factor of (7g + 6h)

The terms factored out are (7g - 6h) and -4

So, the factorization is: -4(7g - 6h)(7g + 6h)

7 0
3 years ago
• I am a fraction less than 1.
Dovator [93]

Answer:

12/15

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Sam had 1 1/2 m of rope. he cut 5/8 m used it for a project. how much rope does sam have left
ludmilkaskok [199]
You have to subtract 5/8 from 11/2. then you will get the answer if you put it in a calculator.
8 0
3 years ago
Salma and jared each threw 5 darts at the target shown. Salma scored 19 points by landing 2 darts in A and 3 in B.How many point
lara31 [8.8K]

Answer:

5

Step-by-step explanation:

Salma and Jared each threw 5 darts at the target shown. Salma scored 19 points by landing 2 darts in A and 3 in B. Jared scored 17 points by landing 1 dart in A and 4 in B. How many points are given for a dart landing in A?

this can be solved using simultaneous equation. Two equations can be formed from the question

2a + 3b = 19  equation 1

1a + 4b = 17    equation 2

Multiply equation 2 by 2

2a + 8b = 34  equation 3

Subtract equation 1 from 3

5b = 15

divide both sides of the equation by 5

b = 3

Substitute for b in equation 1

2a + 3(3) = 19

2a = 9 = 19

collect like terms

2a = 10

divide both sides of the equation by 2

a = 5

6 0
3 years ago
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