Answer:
yes 150.0grams = 150grams
Answer: 0.123 M
Explanation:
According to the neutralization law:
where,
= molarity of 
solution = ?
= volume of solution = 15.00 ml
= molarity of 
solution = 0.100 M
= volume of solution = 18.44 ml
= valency of = 1
= valency of = 1
Therefore, the concentration of the unknown HBr solution is 0.123 M
Answer:
32.8%
Explanation:
All of the Pb⁺² species precipitated as lead(II) cromate, PbCrO₄ (we know this as excess K₂CrO₄ was used).
First we convert 0.130 g of PbCrO₄ into moles, using its molar mass:
- 0.130 g ÷ 323 g/mol = 4.02x10⁻⁴ mol PbCrO₄
There's 1 Pb⁺² mol per PbCrO₄ mol, so in total 4.02x10⁻⁴ moles of Pb⁺² were in the ethanoate sample.
We <u>convert those 4.02x10⁻⁴ moles of Pb into grams</u>:
- 4.02x10⁻⁴ mol * 207 g/mol = 0.083 g Pb
Finally we calculate the percentage composition of Pb:
- 0.083 g Pb / 0.254 g salt * 100% = 32.8%
I think the answer is research and development.
