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Ainat [17]
3 years ago
11

What evidence would support Maria's claim that the fossilized remains are that of a bird, class Aves, instead of a turtle, class

Reptilia? A) the eggs B) a backbone C) a keeled sternum D) warm-bloodedness
Chemistry
2 answers:
lora16 [44]3 years ago
6 0

Your answer would be C.

Ulleksa [173]3 years ago
3 0

Answer:

The correct answer is option c, that is, keeled sternum.

Explanation:

In the given question, there is a need to access the skeleton or the fossilized remains of the species. The turtles possess bony, tough shells that safeguard their body. It exhibits a domed top (carapace) and a flat layer underneath the belly (plastron). The backbones of the turtles are amalgamated with the bones in their shells.  

While, the birds exhibit a lightweight skeleton, which is formed majorly of thin and hollow bones. If the skeleton possesses a breastbone, or the keeled sternum, then what they have found is most probably the nest of the bird.  

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The rays of the sun strike the Earth less directly during winter in the Northern Hemisphere?
noname [10]
The sun's rays hit the Earth at a extreme angle,  which causes the days to become shorter, so yes, the sun's rays do hit the Earth at a extreme angle.
8 0
3 years ago
Suppose a snack bar is burned in a calorimeter and heats 2,000 g water by 20 °C. How much heat energy was released? (Hint: Use t
Salsk061 [2.6K]

The answer is: 167360

6 0
2 years ago
Read 2 more answers
Combustion analysis of a 13.42-g sample of the unknown organic compound (which contains only carbon, hydrogen, and oxygen) produ
kirza4 [7]

<u>Answer:</u> The molecular formula for the given organic compound is C_{18}H_{20}O_2

<u>Explanation:</u>

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

C_xH_yO_z+O_2\rightarrow CO_2+H_2O

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of CO_2=39.61g

Mass of H_2O=9.01g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

<u>For calculating the mass of carbon:</u>

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 39.61 g of carbon dioxide, \frac{12}{44}\times 39.61=10.80g of carbon will be contained.

<u>For calculating the mass of hydrogen:</u>

In 18 g of water, 2 g of hydrogen is contained.

So, in 9.01 g of water, \frac{2}{18}\times 9.01=1.00g of hydrogen will be contained.

Mass of oxygen in the compound = (13.42) - (10.80 + 1.00) = 1.62 g

To formulate the empirical formula, we need to follow some steps:

  • <u>Step 1:</u> Converting the given masses into moles.

Moles of Carbon = \frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{10.80g}{12g/mole}=0.9moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{1g}{1g/mole}=1moles

Moles of Oxygen = \frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{1.62g}{16g/mole}=0.10moles

  • <u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.10 moles.

For Carbon = \frac{0.9}{0.10}=9

For Hydrogen = \frac{1}{0.10}=10

For Oxygen = \frac{0.10}{0.10}=1

  • <u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of C : H : O = 9 : 10 : 1

Hence, the empirical formula for the given compound is C_9H_{10}O

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is :

n=\frac{\text{Molecular mass}}{\text{Empirical mass}}

We are given:

Mass of molecular formula = 268.34 g/mol

Mass of empirical formula = 134 g/mol

Putting values in above equation, we get:

n=\frac{268.34g/mol}{134g/mol}=2

Multiplying this valency by the subscript of every element of empirical formula, we get:

C_{(9\times 2)}H_{(10\times 2)}O_{(1\times 2)}=C_{18}H_{20}O_2

Thus, the molecular formula for the given organic compound is C_{18}H_{20}O_2.

3 0
3 years ago
What is the molar mass of PCL3
antiseptic1488 [7]
The molar mass for PCL3 is 137.33 g/mol
8 0
3 years ago
What is the mass of 2.90 ×1022 molecules of NaOH (Molar mass = 40.0 g/mol)?
ivann1987 [24]
40.0 g ( 1 mole ) --------------- 6.02x10²³ molecules
      ? ? --------------------------- 2.90x10²² molecules

mass = 2.90x10²² * 40.0 /  6.02x10²³

mass = 1.16x10²⁴ / 6.02x10²³

mass = 1.9269 g

hope this helps!

3 0
3 years ago
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