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ki77a [65]
3 years ago
15

Arrange the following elements in order of decreasing ionization energy: Cl, Si, P, Ar *

Chemistry
1 answer:
Elden [556K]3 years ago
7 0

Answer:

Ar > Cl > P > Si.

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10 grams of cocaine helps chalk to grow and the mass was increase a way lot more
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2 years ago
25 POINTS
Rudiy27

EASY AS PIE AND I LIKE PIE

Calcium iodide (CaI2) is an ionic bond, which means that electrons are transferred.  In order for Ca to become the ion Ca2+, the calcium atom must lose 2 electrons. (Electrons have a negative charge, so when an atom loses 2 electrons, its ion becomes more positive.)  In order for I to become the ion I1−, the iodine atom must gain 1 electron. (When an atom gains an electron, its ion will be more negative.)  However, the formula for calcium iodide is CaI2 - there are 2 iodine ions present. This makes sense because the iodine ion has a charge of -1, so two iodine ions have to be present to cancel out the +2 charge of the calcium ion.  Therefore, the calcium atom transfers 2 valence electrons, one to each iodine atom, to form the ionic bond.

IF WRONG, SORRY

8 0
3 years ago
Read 2 more answers
HELP! THIS IS A TIMED QUIZ!!
ivanzaharov [21]

Answer:

A) Age!! Its because even if the object was 1 year old or 100 years old, nothing about the impact would change. However, those other categories depict features that would definitely make an impact. For example as object that is big, fast, and hits at an angle perpendicular to whatever it is moving towards, the impact will be very lage. But if its the opposite and it was small and slow, then the impact crater would not be as large. Good luck on your quiz!!

5 0
2 years ago
HELPP! pls
pshichka [43]

Answer:

"2.48 mole" of H₂ are formed. A further explanation is provided below.

Explanation:

The given values are:

Mole of Al,

= 3.22 mole

Mole of HBr,

= 4.96 mole

Now,

(a)

The number of mole of H₂ are:

⇒  \frac{Mole \ of \ H_2}{3} =\frac{Mole \ of HBr}{6}

or,

⇒  Mole \ of \ H_2=\frac{1}{2}\times Mole \ of \ HBr

⇒                      =\frac{1}{2}\times 4.96

⇒                      =2.48 \ mole

(b)

The limiting reactant is:

= HBr

(c)

The excess reactant is:

= Al

6 0
2 years ago
A 0.885 M solution of KBr whose initial volume is 82.5 mL has more water added until its concentration is 0.500 M. What is the n
4vir4ik [10]

Answer:

V_2=146mL

Explanation:

Hello there!

In this case, since the equation for the calculation of dilutions is:

M_1V_1=M_2V_2

Whereas M is the molarity and V the volume, because the final concentration is lower than the initial. Thus, since we are asked to calculate the final volume, we solve for V2 as follows:

V_2=\frac{M_1V_1}{M_2}=\frac{0.885M*82.5mL}{0.500M}\\\\V_2=146mL

Best regards!

4 0
3 years ago
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