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Nat2105 [25]
3 years ago
15

Draw structures for all constitutional isomers with the molecular

Chemistry
1 answer:
Andre45 [30]3 years ago
4 0
The answer is B
APEX
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These should be as similar as possible to the real thing
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4 years ago
Ethene (c2h4) can be halogenated by this reaction: c2h4( g) + x2( g) ∆ c2h4x2( g) where x2 can be cl2 (green), br2 (brown), or i
scZoUnD [109]

Answer :The correct order for equilibrium constant = K₁ > K₂ >K₃

Ethene is an alkene and X2 is elemental halogen . The reaction between alkene and halogen is known as Halogenation reaction . This reaction involves electrophilic addition mechanism . In this reaction elemental halogen (X₂ ) produces a elctrophile , X⁺ . This electrophile is attracted by the double bond in alkene and attached to it .

Due to addition of electrophile , it produces carbocation intermediate .On this positive carbon , nucleophile attacks , hence , a resultant 1,2-di halide alkane is produced .( in image )

The reaction between ethene ( C₂H₄) and halogen ( X₂) produces 1,2 - dihalide ethane (C₂H₄X₂) . The image shows reaction between chlorine ,Cl₂ , a halogen (X₂) .

The expression for equilibrium constant of reaction between ethene and halogen is given as:

K = \frac{product}{reactant }

Product = C₂H₄X₂ Reactants = C₂H₄ and X₂

K = \frac{[C_2H_4X_2]}{[C_2H_4] [X_2]}

On applying this concept in figures :

Given : Green = Cl₂ Brown = Br₂ Purple = I₂ Grey = Ethene

Grey + Green = 1,2- dihalide ethane

a) Number of Cl₂(green ) = 2

number of ethane ( grey ) = 2

Number of 1,2-dichloride alkane( grey + green ) = 8

Plugging these number in equilibrium constant expression :

K_1 = \frac{8}{2 * 2 } =  \frac{8}{4} = 2

Hence K₁ for ethene + chlorine = 2

b) Number of Br₂(brown ) = 4

number of ethane ( grey ) = 4

Number of 1,2-dibromide alkane( grey + brown ) = 6

On plugging these values in K expression as :

K_2= \frac{6 }{4 * 4 } = \frac{6}{16} =   0.375

Hence K₂ for ethen + Bromine = 0.375

c) Number of I₂(purple ) = 7

number of ethane ( grey ) = 7

Number of 1,2-diiodide alkane( grey + purple ) = 3

On plugging values in K expression as:

K_3 = \frac{3}{7 * 7 } = \frac{3}{49}   =  0.0612

Hence K₃ for ethene + Iodine = 0.0612

So , the order of equilibrium constant (K) from largest to smallest :

K₃ = 0.0612 K₂ = 0.375 K₁= 2

K₁ > K₂ >K₃

7 0
4 years ago
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