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Komok [63]
4 years ago
12

how many seconds are there in 2500 years? (assume 1 year=365 days) express your answer using three significant figures

Chemistry
2 answers:
iragen [17]4 years ago
6 0
The question gives us a conversion factor but we need more:

1 year= 365 days
1 day= 24 hours
1 hour= 60 min
1 min= 60 seconds

2500 years ( \frac{365 days}{1 year} ) ( \frac{24 hours}{1 day} ) ( \frac{60 minutes}{1 hour} ) ( \frac{60 seconds}{1 minute} )= 7.9x10^{10} seconds


julia-pushkina [17]4 years ago
4 0
The answer is:
 7.889 x 10^10 seconds
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sveticcg [70]

do you mean fractional distillation of crude oil ?

if you do then this is what happens:

basically, crude oil is made up of a lot of hydrocarbons so it's put into a fracitonating column to separate these compounds into fractions. the top of the fractionating column is colder whereas the bottom of the column is hotter.

gases, petrol, diesel and kerosene come out near the top of the top of the column because they are shorter chains. substances near the top of the column also have a lower boiling point (since it's cooler and there's less intermolecular forces).

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substances that come out near the bottom of the fracitonating column include fuel oil and bitumen.

these are longer chains of hydrocarbons and bitumen is used for road surfacing.

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5 0
3 years ago
Find Ecell for an electrochemical cell based on the following reaction with [MnO4−]=1.20M, [H+]=1.50M, and [Ag+]=0.0100M. E∘cell
bagirrra123 [75]

Answer:

1.01 V

Explanation:

From Nernst equation;

Ecell= E°cell- 0.0592/n log Q

Where;

Ecell= observed emf of the cell

E°cell= standard emf of the cell

n= number of moles of electrons transferred

Q= reaction quotient

Q= [Ag^+]^3/[MnO4^-] [H^+]^4

Q= [0.01]^3/[1.20] [1.50]^4

Q= 1.65×10^-7

Ecell= 0.88 - 0.0592/3 log 1.65×10^-7

Ecell= 0.88 - [0.0197×(-6.78)]

Ecell= 0.88 + 0.134

Ecell= 1.01 V

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