All categories

2 years ago

Name an atom that loses one electron when it reacts to another atom

1 answer:

4 0

Lithium, Sodium, Potassium; any of the Alkali Metals, which are farthest left on the periodic table. This is because they only have one electron in their outermost shell, so they would rather lose an electron rather than try to gain 7 to achieve that full outer shell.

You might be interested in

Fecl3 reacts with only one of the two compounds aspirin and salicylic acid with which part of a molecule does fecl3 react

lara [203]

FeCl3 very commonly reacts with phenol groups.

hope this helps!!

8 0

2 years ago

Read 2 more answers

What is the theoretical yield of Li3N in grams when 12.8 g of Li is heated with 34.9 g of N2?

Olenka [21]

Answer:- 21.4 grams of $Li_3N$ are formed.

Solution:- The balanced equation is:

$6Li+N_2\rightarrow 2Li_3N$

From this equation, lithium and nitrogen reacts in 6:1 mol ratio. Limiting reactant gives the theoretical yield of the product. We will calculate the grams of the product for the given grams of both the reactants and see which one of them gives the limited amount of the product. This limited amount of the product will be the theoretical yield.

The molar mass of Li is 6.94 gram per mol and for $N_2$ It is 28.02 gram per mol. The molar mass of $Li_3N$ is 34.83 gram per mol. The calculations for the grams of the product for given grams of both the reactants are shown below:

$12.8gLi(\frac{1molLi}{6.94gLi})(\frac{2molLi_3N}{6molLi})(\frac{34.83gLi_3N}{1molLi_3N})$

= $21.4gLi_3N$

$34.9gN_2(\frac{1molN_2}{28.02gN_2})(\frac{2molLi_3N}{1molN_2})(\frac{34.83gLi_3N}{1molLi_3N})$

= $86.8gLi_3N$

From above calculations, Li gives least amount of the product. So, 21.4 g of $Li_3N$ are formed.

4 0

2 years ago

Assuming all the nh3 dissolves and that the volume of the solution remains at 0.300 l , calculate the ph of the resulting soluti

barxatty [35]

<span>Assume p=735 Torr V= 7.6L R=62.4 T= 295 PV-nRT (735 Torr)(7.60L)= n (62.4Torr-Litres/mole-K)(295K) 0.30346 moles of NH3 Find moles 0.300L solution of 0.300 M HCL = 0.120 moles of HCL 0.30346 moles of NH3 reacts with 0.120 moles of HCL producing 0.120 moles of NH4+ ION, and leaving 0.18346 mole sof NH3 behind Find molarity 0.120 moles of NH4+/0.300L = 0.400 M NH4+ 0.18346 moles of NH3/0.300L = 0.6115 M NH3 NH4OH --> NH4 & OH- Kb = [NH4+][OH]/[NH4OH] 1.8 e-5=[0.300][OH-]/[0.6115] [OH-]=1.6e-5 pOH= 4.79 PH=9.21 .</span>

3 0

3 years ago

What exactly is a proton? Is it a member of the periodic table?

Pavel [41]

The atomic number is the number of protons in the nucleus of an atom. The number of protons define the identity of an element (i.e., an element with 6 protons is a carbon atom, no matter how many neutrons may be present).

4 0

2 years ago

A partir de lo propuesto por Bohr en 1913, que postulado es correcto:

TEA [102]

Answer:

Primer postulado:

Así Bohr asumió que el átomo de hidrógeno puede existir solo en ciertos estados discretos, los cuales son denominados estados estacionarios del átomo. En el átomo no hay emisión de radiación electromagnética mientras el electrón no cambia de órbita.

Explanation:

4 0

2 years ago