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s2008m [1.1K]
3 years ago
11

What is the mass of 0.78 mol Mg(NO3),? Make sure to round to the correct number of sig figs and to include the unit in your fina

l answer
Chemistry
1 answer:
Oxana [17]3 years ago
7 0

Answer:

67.08 g

Explanation:

you firts write what u know

then u calculate the molar mass of the salt

then according to the formula mass= number of mols × molar mass you find the mass

m= mass

n= number of mol

M= molar mass i hope this helps

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Identify one factor represented in the diagram that is used to classify the ten types of clouds
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Middle clouds
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6 0
3 years ago
Please help make sure its correct thanks
Wewaii [24]

The empirical formula of metal iodide : CoI₃(Cobalt(III) Iodide)

<h3>Further explanation</h3>

13.02 g sample of Cobalt , then mol Co(MW=58.933 g/mol) :

\tt mol=\dfrac{mass}{Ar}=\\\\mol=\dfrac{13.02~g}{58.933}\\\\mol=0.221

Mass of metal iodide formed : 97.12 g, so mass of Iodine :

\tt =mass~metal~iodide-mass~Cobalt\\\\=97.12-13.02\\\\=84.1~g

Then mol iodine (MW=126.9045 g/mol) :

\tt \dfrac{84.1}{126.9045}=0.663

mol ratio of Cobalt and Iodine in the compound :

\tt 0.221\div 0.663=1\div 3

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