What is the mass of 0.78 mol Mg(NO3),? Make sure to round to the correct number of sig figs and to include the unit in your fina
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Answer:
Explanation:
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In this case, the undergoing chemical reaction is:
Next, we identify the limiting reactant by computing the available moles of ethane and the moles of ethane consumed by 60.0 grams of oxygen:
Thus, we notice there are less available moles, for that reason, the ethane is the limiting reactant. Finally, we can compute the produced moles of water by:
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