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lesantik [10]
4 years ago
7

When a match burns it's mass decreases. Is this a violation of the law of conservation of mass?

Chemistry
2 answers:
svetlana [45]4 years ago
3 0
No. The mass is released into the air.
Elan Coil [88]4 years ago
3 0
No. The gas coming from it is released into the air as mass cant just disappear.
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The solubility of BaCO3(s) in water at a certain temperature is 4.4 10–5 mol/L. Calculate the value of Ksp for BaCO3(s) at this
azamat

Answer : The value of K_{sp} for BaCO_3 is 19.36\times 10^{-10}mole^2/L^2.

Solution : Given,

Solubility of BaCO_3 in water = 4.4\times 10^{-5}mole/L

The barium carbonate is insoluble in water, that means when we are adding water then the result is the formation of an equilibrium reaction between the dissolved ions and undissolved solid.

The equilibrium equation is,

                            BaCO_3\rightleftharpoons Ba^{2+}+CO^{2-}_3

Initially                   -                   0        0

At equilibrium       -                   s         s

The Solubility product will be equal to,

K_{sp}=[Ba^{2+}][CO^{2-}_3]

K_{sp}=s\times s=s^2

[Ba^{2+}]=[CO^{2-}_3]=s=4.4\times 10^{-5}mole/L

Now put all the given values in this expression, we get the value of solubility constant.

K_{sp}=(4.4\times 10^{-5}mole/L)^2=19.36\times 10^{-10}mole^2/L^2

Therefore, the value of K_{sp} for BaCO_3 is 19.36\times 10^{-10}mole^2/L^2.

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How much work is required to lift a 0.500 kg block 18.5 m?
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Answer:

Work = 90.65 j

Explanation:

Given data:

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