<span>HCl<span>(aq)</span>+NaOH<span>(aq)</span>→NaCl<span>(aq)</span>+<span>H2</span>O<span>(l)</span></span>
As you can see here, one mole of acid neutralizes one mole of base.
We use the concentration equation, which states that,
<span>c=<span>nv</span></span>
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n is the number of moles
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v is the volume of solution
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Rearranging for moles, we get,
<span>n=c⋅v</span>
So, we have:
<span><span>n<span>NaOH</span></span>=0.1 M⋅0.05 L</span>
<span>=0.005 mol</span>
Since one mole of acid neutralizes one mole of base, then we must have: <span><span>n<span>HCl</span></span>=<span>n<span>NaOH</span></span></span>.
And so,
<span><span>c<span>HCl</span></span>=<span><span>n<span>HCl</span></span><span>v<span>HCl</span></span></span></span>
<span>=<span><span>0.005 mol</span><span>0.03 L</span></span></span>
<span>≈0.17 <span>M</span></span>
Answer:
Please make it full I'm not seeing it
Answer:
2CO 2NO → 2CO2 N2 : Balanced
6CO2 6H2O → C6H12O6 : Unbalanced
H2CO3 → H2O CO2 : Balanced
2Cu O2 → CuO : Unbalanced
Explanation:
1.) 2CO 2NO → 2CO2 N2
2 Carbon 2
4 Oxygen 4
2 Nitrogen 2
The amount of atoms of each element on each side of the equation are the same therefore the equation is balanced.
2.) 6CO2 6H2O → C6H12O6 O2
6 Carbon 6
12 Oxygen 8
12 Hydrogen 12
The amount of oxygen atoms is different on both sides of the equation therefore the equation is not balanced.
3.) H2CO3 → H2O CO2
2 Hydrogen 2
1 Carbon 1
3 Oxygen 3
The amount of atoms of each element is the same on both sides of the equation therefore the equation is balanced.
2Cu O2 → CuO.
2 Cu 2
2 O 1
The amount of oxygen atoms is different on both sides of the equation therefore the equation is not balanced.
False because the sugar is just changing it’s form