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Alex_Xolod [135]
3 years ago
10

-69=-3m-2(5m+2) help me solve plssss

Mathematics
1 answer:
sasho [114]3 years ago
5 0

-3m-2(5m+2)=-69\ \ \ |\text{use distributive property}\\\\-3m-2(5m)-2(2)=-69\\\\-3m-10m-4=-69\\\\-13m-4=-69\ \ \ \ |+4\\\\-13m=-65\ \ \ \ \ |:(-13)\\\\\boxed{m=5}

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Use long division to find the quotient of 990 and 45.
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22

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because if you divide 45 first it will be wrong so you must always first will the biggest number in your problem

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What type of triangle is formed by joining the points D(7, 3), E(8, 1), and
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C

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an initial investment of $9000 grows at an annual interest rate of 5% compounded continuously. how long will it take to double t
tino4ka555 [31]

Answer:

20 years

Step-by-step explanation:

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8 0
3 years ago
Please help!
Gemiola [76]

The earning of the salesperson is an illustration of a linear function.

The possible functions in the two scenarios are: \mathbf{I(s) = 0.1s + 2500} and \mathbf{I(s) = 0.05s + 2000}\\

The function is given as:

\mathbf{I(s) = 0.1s + 2000}

When the base salary is increased, a possible function is:

\mathbf{I(s) = 0.1s + 2500}

This is so, because 2500 is greater than 2000

When the commission rate is decreased, a possible function is:

\mathbf{I(s) = 0.05s + 2000}\\

This is so, because 0.05 is less than 0.1

So, the possible functions in the two scenarios are:

\mathbf{I(s) = 0.1s + 2500} and \mathbf{I(s) = 0.05s + 2000}\\

See attachment for the graphs of both functions

Read more about linear equations at:

brainly.com/question/21981879

5 0
3 years ago
Mr.james runs a petting zoo. he records the number of visitors each week,v, t weeks, after opening the petting zoo. according to
melisa1 [442]

Answer:

\large \boxed{\text{19 visitors/mo}}

Step-by-step explanation:

The average rate of change is the change in the number of visitors divided by the change in the number of months.

1. Change in number of  visitors  

Change in visitors = 182 -125 = 57 visitors

2. Change in number of weeks

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3. Average rate of change

\begin{array}{rcl}\text{Average rate of change} &= &\dfrac{\text{change in visitors}}{\text{change in months}}\\\\&= &\dfrac{\text{57 visitors}}{\text{3 mo}}\\\\& = & \textbf{19 visitors/mo}\\\end{array}\\\text{The average rate of change is $\large \boxed{\textbf{19 visitors/mo}}$}

5 0
4 years ago
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