J = 3 + 25
J = 28 ← answer
Answer:
2000
Step-by-step explanation:
In the equation, there is 0.02 attached to the x. This means multiplication. TO get rid of the 0.02, you need to do the opposite of multiplication. That is division.
Divide both sides by 0.02.


Answer:
I=\frac{t^2}{2}
Step-by-step explanation:
From exercise we have that x=t, t>0. Because A(t) be the area of the region in the first quadrant, we get that x started at 0. The limits for y are the following e-x and e. We get the integral :
I=\int\limits^0_t \int\limits^{e}_{e-x} 1 dy dx
I=\int\limits^0_t [y]_{e-x}^{e} dx
I=\int\limits^0_t (e-e+x) dx
I=\int\limits^0_t {x} \, dx
I=[\frac{x^2}{2} ]_{0}^{t}
I=\frac{t^2}{2}
Answer:
8977
Step-by-step explanation:
Hello,

thanks