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3 years ago

9

I need help please?????

1 answer:

Advocard [28]3 years ago

5 0

6×2 - 3×3

12 - 9

3

The answer is 3

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If 16+4x is 10 more than 14, what is the value of 8x?

sattari [20]

16 + 4x = 10 + 14

16 + 4x = 24.

4x = 24 - 16

4x = 8

x = 8 ÷ 4

x = 2

8x = 2 × 8

8x = 16

Final answer = 16.

3 0

3 years ago

kherson [118]

Answer:

Point N(4, 1)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality<u> </u>

<u>Algebra I</u>

Coordinates (x, y)
Functions
Function Notation
Terms/Coefficients
Anything to the 0th power is 1
Exponential Rule [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$
Exponential Rule [Root Rewrite]: $\displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}$

<u>Calculus</u>

Derivatives

Derivative Notation

Derivative of a constant is 0

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]: $\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Step-by-step explanation:

<u>Step 1: Define</u>

<u /> $\displaystyle y = \sqrt{x - 3}$ <u />

<u /> $\displaystyle y' = \frac{1}{2}$ <u />

<u />

<u>Step 2: Differentiate</u>

[Function] Rewrite [Exponential Rule - Root Rewrite]: $\displaystyle y = (x - 3)^{\frac{1}{2}}$
Chain Rule: $\displaystyle y' = \frac{d}{dx}[(x - 3)^{\frac{1}{2}}] \cdot \frac{d}{dx}[x - 3]$
Basic Power Rule: $\displaystyle y' = \frac{1}{2}(x - 3)^{\frac{1}{2} - 1} \cdot (1 \cdot x^{1 - 1} - 0)$
Simplify: $\displaystyle y' = \frac{1}{2}(x - 3)^{-\frac{1}{2}} \cdot 1$
Multiply: $\displaystyle y' = \frac{1}{2}(x - 3)^{-\frac{1}{2}}$
[Derivative] Rewrite [Exponential Rule - Rewrite]: $\displaystyle y' = \frac{1}{2(x - 3)^{\frac{1}{2}}}$
[Derivative] Rewrite [Exponential Rule - Root Rewrite]: $\displaystyle y' = \frac{1}{2\sqrt{x - 3}}$

<u>Step 3: Solve</u>

<em>Find coordinates</em>

<em />

<em>x-coordinate</em>

Substitute in <em>y'</em> [Derivative]: $\displaystyle \frac{1}{2} = \frac{1}{2\sqrt{x - 3}}$
[Multiplication Property of Equality] Multiply 2 on both sides: $\displaystyle 1 = \frac{1}{\sqrt{x - 3}}$
[Multiplication Property of Equality] Multiply √(x - 3) on both sides: $\displaystyle \sqrt{x - 3} = 1$
[Equality Property] Square both sides: $\displaystyle x - 3 = 1$
[Addition Property of Equality] Add 3 on both sides: $\displaystyle x = 4$

<em>y-coordinate</em>

Substitute in <em>x</em> [Function]: $\displaystyle y = \sqrt{4 - 3}$
[√Radical] Subtract: $\displaystyle y = \sqrt{1}$
[√Radical] Evaluate: $\displaystyle y = 1$

∴ Coordinates of Point N is (4, 1).

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Derivatives

Book: College Calculus 10e

4 0

3 years ago

What is the slope and y-intercept of this line?

RUDIKE [14]

THE SLOPE IS 1 AND THE Y INTERCEPT IS -3, the x is equal to 1, and the -3 is in the place of the y intercept so your answer would be A.

6 0

3 years ago

Eva has £6.05 in her moneybox.

PIT_PIT [208]

Answer:

11 of 20p, 22 of 10p and 33 of 5p

Step-by-step explanation:

Eva has 20p, 10p and 5p coins, total of £6.05 = 605p

Let 20p=x, 10p=y, 5p=z

<u>Then</u>:

20x + 10y + 5z = 605
y : x = 2 : 1 ⇒ x= y/2
y : z = 2 : 3 ⇒ z= 3y/2

<u>Rewriting the first equation considering next two:</u>

10y + 10y + 7.5y = 605
27.5y = 605
y= 605/27.5
y= 22
x= y/2 = 22/2 = 11
z = 3y/2 = 3*11 = 33

<u>Answer:</u> 11 of 20p coins, 22 of 10p coins and 33 of 5p coins

3 0

3 years ago

A limousine company charges a fixed cost for a limousine and an hourly rate for it's driver. It cost $500 to rent a limousine fo

mr Goodwill [35]

Answer: the fixed cost to rent the limousine is $200

Step-by-step explanation:

Let x represent the fixed cost rent the limousine.

Let y represent the cost of of hiring the driver of the limousine per hour.

It cost $500 to rent a limousine for 5 hours. This means that

x + 5y = 500 - - - - - - - - - - -1

It costs 800 to rent a limousine for 10 hours. This means that

x + 10y = 800 - - - - - - - - - - -2

Subtracting equation 2 from equation 1, it becomes

- 5y = - 300

y = - 300 /- 5

y = 60

Substituting y = 60 into equation 1, it becomes

x + 5 × 60 = 500

x + 300 = 500

x = 500 - 300

x = 200

5 0

4 years ago

Read 2 more answers