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ddd [48]
3 years ago
14

Fast pls..,.,,..,,.,.,.

Chemistry
2 answers:
NeX [460]3 years ago
7 0
The answer is D) gills. Gills are how fish breath.
OLga [1]3 years ago
4 0
I believe the answer is gills

Fish's use gills to breathe, so tadpoles should use gills too

hope this helps

(got the info from a documentary i watched a couple years ago)
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5. Which of these elements has the greatest atomic radius? *<br> Be<br> Mg<br> Ra<br> Ba
trapecia [35]
The answer is Ra
Atomic number for Be is 4

Atomic number for Mg 12

Atomic number for Ra 88

Atomic number for Ba 56
5 0
3 years ago
Isomers have the same physical properties because the chemical formulas are identical. True False
Luda [366]
The statement is False.
The molecular (chemical) formulas are same in case of isomers but the arrangement of atoms is different in them. The physical properties are determined by the arrangement of atoms within the molecule.

Since the arrangement of atoms is different in case of isomers, the Physical Properties will also be different.
5 0
3 years ago
How many milliliters of water at 25.0°C with a density of 0.997 g/mL must be mixed with 163 mL of coffee at 97.9°C so that the r
Stolb23 [73]

Answer:

248 mL

Explanation:

According to the law of conservation of energy, the sum of the heat absorbed by water (Qw) and the heat released by the coffee (Qc) is zero.

Qw + Qc = 0

Qw = -Qc [1]

We can calculate each heat using the following expression.

Q = c × m × ΔT

where,

  • c: specific heat
  • m: mass
  • ΔT: change in the temperature

163 mL of coffee with a density of 0.997 g/mL have a mass of:

163 mL × 0.997 g/mL = 163 g

From [1]

Qw = -Qc

cw × mw × ΔTw = -cc × mc × ΔTc

mw × ΔTw = -mc × ΔTc

mw × (54.0°C-25.0°C) = -163 g × (54.0°C-97.9°C)

mw × 29.0°C = 163 g × 43.9°C

mw = 247 g

The volume corresponding to 247 g of water is:

247 g × (1 mL/0.997 g) = 248 mL

8 0
3 years ago
A complexometric titration can also be used to determine the amount of calcium in milk. The calcium concentration in milk is typ
Morgarella [4.7K]

Answer:

d

Explanation:answer is d on edg 2020

6 0
3 years ago
when 824 J of heat is added to 9 grams of oil at 30°c , the temperature increases to 87°C. what is the specific heat of the oil
sattari [20]

Answer:

c = 1.61 j/g.°C

Explanation:

Given data:

Mass of oil = 9 g

Heat added = 824 j

Initial temperature =  30°C

Final temperature = 87°C

Specific heat of oil = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = Final temperature - final temperature

ΔT = 87°C - 30°C

ΔT = 57 °C

Q = m.c. ΔT

824 j = 9 g × c ×  57 °C

824 j = 513 g. °C × c

c = 1.61 j/g.°C

5 0
3 years ago
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