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Gnom [1K]
3 years ago
11

What is the molality of a solution of 12.9 g of fructose (C6H12O6) in 31.0 g of water?

Chemistry
1 answer:
jasenka [17]3 years ago
8 0

Answer:

2.31 m C₆H₁₂O₆

Explanation:

Hope this helps

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A gas made up of homonuclear diatomic molecules escapes through a pinhole times as fast as gas. Write the chemical formula of th
Art [367]

Answer:

The answer to the question is

Chlorine Cl₂

Explanation:

Graham's Law of effusion states that the rate of effusion of  a gas is inversely proportional to the square root of the molar mass

\frac{R_{1} }{R_{2}} = \sqrt{ \frac{M_{2}}{M_{1}} }

0.238 = \sqrt{ \frac{4}{M_{1}} }

Therefore M₁ = 4÷0.238² = 70.61

Hence the mass of the gas is 70.61, that is X₂ = 70.61  or the molar mass of the element X = 70.61÷2 = 35.308 ≅35.453 Hence the gas is chlorine Cl₂

6 0
3 years ago
three students made multiple weighings of a copper cylinder each using a different balance. Describe the accuracy and precision
ch4aika [34]
I think that you have put up an incomplete question. However, i am answering the question based on my research and knowledge. 

Lissa- accuracy and precision are both low
Lamont- accuracy and precision are definitely high
<span>Leigh Anne- accuracy is low but precision is definitely high.
</span>
I hope that this is the answer that you were looking for and the answer has definitely come to your desired help.
3 0
3 years ago
Calculate the number of milliliters of 0.710 M Ba(OH)2 required to precipitate all of the Mn2+ ions in 161 mL of 0.796 M KMnO4 s
USPshnik [31]

<u>Answer:</u> The volume of barium hydroxide is 183 mL.

<u>Explanation:</u>

To calculate the moles of cadmium nitrate, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}       .....(1)

Molarity of MnSO_4 = 0.796 M

Volume of MnSO_4 = 161 mL = 0.161 L   (Conversion factor: 1 L = 1000 mL)

Putting values in equation 1, we get:

0.796mol/L=\frac{\text{Moles of }MnSO_4}{0.161L}\\\\\text{Moles of }MnSO_4=0.13mol

The chemical equation for the reaction of manganese sulfate and barium hydroxide follows:

MnSO_4(aq.)+Ba(OH)_2(aq.)\rightarrow Mn(OH)_2(s)+BaSO_4(aq.)

By Stoichiometry of the reaction:

1 mole of manganese sulfate reacts with 1 mole of barium hydroxide.

So, 0.13 moles of manganese sulfate will react with = \frac{1}{1}\times 0.13=0.13mol of barium hydroxide

Now, calculating the volume of barium hydroxide by using equation 1, we get:

Moles of barium hydroxide = 0.13 moles

Molarity of barium hydroxide = 0.710 M

Putting values in equation 1, we get:

0.710mol/L=\frac{0.13mol}{\text{Volume of barium hydroxide}}\\\\\text{Volume of barium hydroxide}=0.183L

Converting this into milliliters, we use the conversion factor:

1 L = 1000 mL

So, 0.183L=0.183\times 1000=183mL

Hence, the volume of barium hydroxide is 183 mL.

7 0
3 years ago
24 POINTS!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
astraxan [27]
<span>Force = total mass * acceleration = 330 * 4 = 1320 N so D is correct !!

</span>
3 0
3 years ago
Read 2 more answers
Calculate the work done when an ideal gas expands isothermally and reversibly in a piston and cylinder assembly for expansion of
pantera1 [17]

Answer:

W=5743.1077\ J

Explanation:

The expression for the work done is:

W=RT \ln \left( \dfrac{P_1}{P_2} \right)

Where,

W is the amount of work done by the gas

R is Gas constant having value = 8.314 J / K mol

T is the temperature

P₁ is the initial pressure

P₂ is the final pressure

Given that:

T = 300 K

P₁ = 10 bar

P₂ = 1 bar

Applying in the equation as:

W=8.314\times 300 \ln \left( \dfrac{10}{1} \right)

W=300\times \:8.314\ln \left(10\right)

W=2.30258\times \:2494.2

W=5743.1077\ J

5 0
3 years ago
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