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Nataliya [291]
3 years ago
9

If an isotope decays by the process of beta emission, ___.

Chemistry
2 answers:
adoni [48]3 years ago
7 0

Answer: The atomic number changes

Explanation: You're welcome ;)

Kaylis [27]3 years ago
3 0
1. Decreases by 4. (B)
2. The atomic number changes. (B)
3. 56/26 Fe. (C)
4. Potassium-40;t1/2=25 days. (B)
5. Takes place in the upper atmosphere. (A)
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Convert the following to Celsius
Naya [18.7K]

9. (80-32)5/9

48×5/9

240/9

26.66°C

9. (90-32)5/9

58×5/9

32.22°C

10 (212-32)5/9

180×5/9

20×5

100°C

8 0
3 years ago
How much heat must be absorbed by 125 g of ethanol to change its temperature from 21.5 ∘C to 34.8 ∘C? (Specific heat capacity of
Katarina [22]

Answer:

Option D. 4.02 kJ

Explanation:

A simple calorimetry problem

Q = m . C . ΔT

ΔT = Final T° - Initial T°

C = Specific heat capacity

m = mass

Let's replace the data

Q = 125 g . 2.42 J/g∘C . (34.8°C -21.5 °C)

Q= 4023.25 J

We must convert the answer to kJ

4023.25 J . 1kJ /1000 =4.02kJ

3 0
3 years ago
1. Marisa determined the melting point of a substance to be 24.5C. Find the percent error of her measurement if the actual melti
USPshnik [31]

Answer:

\%\ Error = 21.5\%

Explanation:

Given

Measured = 24.5

Actual = 31.2

Required

Determine the percentage error

First, we need to determine the difference in the measurement

Difference = |Actual - Measured|

Difference = |31.2 - 24.5|

Difference = |6.7|

Difference = 6.7

The percentage error is calculated as thus:

\%\ Error = \frac{Difference * 100\%}{Actual}

\%\ Error = \frac{6.7 * 100\%}{31.2}

\%\ Error = \frac{670\%}{31.2}

\%\ Error = 21.4743589744\%

\%\ Error = 21.5\% <em>approximated</em>

6 0
3 years ago
What are two ways in which white blood cells fight pathgons that have entered the body​
crimeas [40]

Answer:

Answer c i believe

Explanation:

3 0
3 years ago
Which subatomic particle gives off visible light when it drops back down to a lower energy state?
icang [17]

Answer:

Option C = electron

Explanation:

Electrons are responsible for the production of colored light.

Electron:

The electron is subatomic particle that revolve around outside the nucleus and has negligible mass. It has a negative charge.

Symbol= e-

Mass= 9.10938356×10⁻³¹ Kg

It was discovered by j. j. Thomson in 1897 during the study of cathode ray properties.

How electrons produce the colored light:

Excitation:

When the energy is provided to the atom the electrons by absorbing the energy jump to the higher energy levels. This process is called excitation. The amount of energy absorbed by the electron is exactly equal to the energy difference of orbits.

De-excitation:

When the excited electron fall back to the lower energy levels the energy is released in the form of radiations. this energy is exactly equal to the energy difference between the orbits. The characteristics bright colors are due to the these emitted radiations. These emitted radiations can be seen if they are fall in the visible region of spectrum.

Other process may involve,

Fluorescence:

In fluorescence the energy is absorbed by the electron having shorter wavelength and high energy usually of U.V region. The process of absorbing the light occur in a very short period of time i.e. 10 ∧-15 sec. During the fluorescence the spin of electron not changed.

The electron is then de-excited by emitting the light in visible and IR region. This process of de-excitation occur in a time period of 10∧-9 sec.

Phosphorescence:

In phosphorescence the electron also goes to the excitation to the higher level by absorbing the U.V radiations. In case of Phosphorescence the transition back to the lower energy level occur very slowly and the spin pf electron also change.

5 0
3 years ago
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