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Nataliya [291]
3 years ago
9

If an isotope decays by the process of beta emission, ___.

Chemistry
2 answers:
adoni [48]3 years ago
7 0

Answer: The atomic number changes

Explanation: You're welcome ;)

Kaylis [27]3 years ago
3 0
1. Decreases by 4. (B)
2. The atomic number changes. (B)
3. 56/26 Fe. (C)
4. Potassium-40;t1/2=25 days. (B)
5. Takes place in the upper atmosphere. (A)
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Name each of the isotope
Alex73 [517]

Answer:

Examples of radioactive isotopes include carbon-14, tritium (hydrogen-3), chlorine-36, uranium-235, and uranium-238.

8 0
2 years ago
Read 2 more answers
6. The graph below shows the heating curve for ethanol (from –200C to 150C). Calculate the amount of heat (kJ) required for each
Kazeer [188]

This problem is providing the heating curve of ethanol showing relevant data such as the initial and final temperature, melting and boiling points, enthalpies of fusion and vaporization and specific heat of solid, liquid and gaseous ethanol, so that the overall heat is required and found to be 1.758 kJ according to:

<h3>Heating curves:</h3>

In chemistry, we widely use heating curves in order to figure out the required heat to take a substance from a temperature to another. This process may involve sensible heat and latent heat, when increasing or decreasing the temperature and changing the phase, respectively.

Thus, since ethanol starts off solid and end up being a vapor, we will find five types of heat, three of them related to the heating-up of ethanol, firstly solid, next liquid and then vapor, and the other two to its fusion and vaporization as shown below:

Q_T=Q_1+Q_2+Q_3+Q_4+Q_5

Hence, we begin by calculating each heat as follows, considering 1 g of ethanol is equivalent to 0.0217 mol:

Q_1=0.0217mol*111.5\frac{J}{mol*\°C}[(-114.1\°C)-(-200\°C)] *\frac{1kJ}{1000J} =0.208kJ\\&#10;\\&#10;Q_2=0.0217mol*4.9\frac{kJ}{mol} =0.106kJ\\&#10;\\&#10;Q_3=0.0217mol*112.4\frac{J}{mol*\°C}[(78.4\°C)-(-114.1\°C)] *\frac{1kJ}{1000J} =0.470kJ\\&#10;\\&#10;Q_4=0.0217mol*38.6\frac{kJ}{mol} =0.838kJ\\&#10;\\&#10;Q_5=0.0217mol*87.5\frac{J}{mol*\°C}[(150\°C)-(78.4\°C)] *\frac{1kJ}{1000J} =0.136kJ

Finally, we add them up to get the result:

Q_T=0.208kJ+0.106kJ+0.470kJ+0.838kJ+0.136kJ\\&#10;\\&#10;Q_T=1.758kJ

Learn more about heating curves: brainly.com/question/10481356

7 0
2 years ago
Drop your insta gang’s <br> Let’s be friends
Zanzabum
Why don’t you have friends?
6 0
2 years ago
Could you separate the sodium from the chlorine by crushing the salt crystals
Zigmanuir [339]
No, you cannot.

The distinction is made in the fact that the sodium and chlorine atoms are bonded chemically, while the crushing of the salt is a physical change. A physical change is one that does not have the ability to change the identity of the substance. Such changes include crushing, boiling, melting. In order to separate the chlorine and sodium atoms, you must make them undergo a chemical change, for example add the salt to sulfuric acid and make it react.
6 0
3 years ago
Please answer this correctly!
Marina CMI [18]

Answer:

International is the answer duh

4 0
1 year ago
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