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Alexeev081 [22]
2 years ago
14

Concentration data is commonly monitored during a reaction to determine the order with respect to a reactant. Consider the types

of observations listed, and determine which order is likely for that reactant. Assume all other factors are held constant. The reaction rate increases in direct proportion to the concentration of the reactant in solution.
1. An increase in the concentration of the reactant in solution causes the reaction rate to increase exponentially.
a. first order.
b. second order.
c. zero order.
2. The reaction rate is constant regardless of the amount of reactant in solution.
a. first order.
b. second order.
c. zero order.
3. The reaction rate increases in direct proportion to the concentration of the reactant in solution.
a. first order.
b. second order.
c. zero order.
Chemistry
1 answer:
alexira [117]2 years ago
6 0

Answer:

1) first order

2) zero order

3) second order

Explanation:

For a first order reaction, the concentration of the reactants varies exponentially with the rate of reaction. The curve of a first order reaction shows an exponential relationship between the rate of reaction and the change in the concentration of reactants.

For a zero order reaction, the rate of reaction is independent of the concentration of the reactants. So, regardless of the amount of reactant in solution, the rate of reaction is constant.

For a second reaction, the reaction rate increases in direct proportion to the concentration of the reactant in solution.

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How many grams of Sg is required to produce 83.10 g SF6? S: +24F--&gt;8SF
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Answer : The mass of S_8 required is 18.238 grams.

Explanation : Given,

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Molar mass of SF_6 = 146 g/mole

Molar mass of S_8 = 256.52 g/mole

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First we have to determine the moles of SF_6.

\text{Moles of }SF_6=\frac{\text{Mass of }SF_6}{\text{Molar mass of }SF_6}=\frac{83.10g}{146g/mole}=0.569moles

Now we have to determine the moles of S_8.

From the balanced chemical reaction we conclude that,

As, 8 moles of SF_6 produced from 1 mole of S_8

So, 0.569 moles of SF_6 produced from \frac{0.569}{8}=0.0711 mole of S_8

Now we have to determine the mass of S_8.

\text{Mass of }S_8=\text{Moles of }S_8\times \text{Molar mass of }S_8

\text{Mass of }S_8=(0.0711mole)\times (256.52g/mole)=18.238g

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